Find the GCF of 260,80,50
1 answer:
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Answer:
Step-by-step explanation:
(a) The function ...
can be evaluated for x=-2√2 to get ...
The point (-2√2, 1) is on the graph of f(x).
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(b) Likewise, we can evaluate for x=2:
The point on the graph is (2, 0.8).
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(c) From part (a), we know that f(-2√2) = 1. Since the function is even, this means that f(2√2) = 1. The graph is a maximum at those points, so there are no other values for which f(x) = 1.
The points (±2√2, 1) are on the graph.
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(d) There are no values of x for which f(x) is undefined. The domain is all real numbers.
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(e) The only x-intercept is at the origin, (0, 0). The x-axis is a horizontal asymptote.
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(f) The only y-intercept is at the origin, (0, 0).
