Answer:
Step-by-step explanation:
2x+2≤x+4≤3x+4
means : 2x+2≤x+4 ...(1) and x+4≤3x+4
(1) : 2x-x≤4-2 so : x≤2....(*)
(2) :3x+4 ≥x+4 .... 3x-x ≥ 0 so: x≥0 ....(**)
by (*) and (**) : 0≤x≤2 so : A=0 and B = 2
Answer:
(3 x + 5) (x + 5)
Step-by-step explanation:
Factor the following:
3 x^2 + 20 x + 25
Hint: | Factor 3 x^2 + 20 x + 25 by finding factors of 3×25 whose sum is 20.
Factor the quadratic 3 x^2 + 20 x + 25. The coefficient of x^2 is 3 and the constant term is 25. The product of 3 and 25 is 75. The factors of 75 which sum to 20 are 5 and 15. So 3 x^2 + 20 x + 25 = 3 x^2 + 15 x + 5 x + 25 = 5 (3 x + 5) + x (3 x + 5):
5 (3 x + 5) + x (3 x + 5)
Hint: | Factor common terms from 5 (3 x + 5) + x (3 x + 5).
Factor 3 x + 5 from 5 (3 x + 5) + x (3 x + 5):
Answer: (3 x + 5) (x + 5)
Answer:
45
Step-by-step explanation:
Answer:
Length = 7
Width = 15
Step-by-step explanation:
L= x
W= x-8
2x+2(x-8)=44
Well, here is how i would do it.
We start with 225, at a rate of 15% per year. Assuming your answers are in years and not months, we will increase by this increment; years.
So, we start with 225, and a 15%, or .15, increase. So what we would do, it take 225 times .15. One way ive learned to do this (via algebra class) is that you can times it by 1.15 to make it quicker, this just takes out the adding step.
So after one year, we would have a total of 258.75, or about 259 wolves.
after two years, we would have about 298 (we cant have a half of a wolf!)
after 3 years, we would have about 343 wolves.
after 4 years, we would have about 394 ish
after 5 years, we would have about 453
after 6 years, we would have about 521.
So, it would take about 5 and a half years, if thats an option choice.
