y = -3(x<span> - 2)^2 + 1 </span>x<span>-coordinate of vertex: </span>x<span> = -b/(2a) = -12/-6 = 2 y-coordintae of vertex: y(2) = -12 + 24 - 11 = 1 </span>Vertex form: y = -3(x<span> - 2)^2 + 1 Check. Develop y to get back to standard form: y = -3(</span>x^2 - 4x + 4) + 1 = -3x<span>^2 + </span>12x<span> - </span>11<span>. </span>
9514 1404 393
Answer:
A
Step-by-step explanation:
The axis of symmetry of quadratic ax²+bx+c is x=-b/(2a). For the given equation, the axis of symmetry is ...
x = -4/(2(3/2)) = -4/3
The only graph with its vertex at x=-4/3 is graph A.
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<em>Additional comment</em>
You can also make the correct choice by evaluating the equation at a couple of different values of x. Convenient ones are x= -1, or 0, or +1. The value at x=0 is the y-intercept, (0, -2), which seems to be a point on all of the graphs. The value at x=1 is 3/2+4-2 = 3.5, which looks like it is only seen on graph A.
Answer:
15
Step-by-step explanation:
D. Sasha's method is exponential because it increases by a fixed factor, and Mona's method is linear because it increases by a fixed number.
Hope this helps!~
