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Cerrena [4.2K]
3 years ago
8

What is the fourth number if three of the numbers are 80, 95, and 85?

Mathematics
2 answers:
krok68 [10]3 years ago
8 0

Answer:

88

Step-by-step explanation:

The answer is 88 because that is the mean, or average or the three numbers.

Strike441 [17]3 years ago
3 0
100 because it goes up 15 and 5
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Which are solutions to the equation below?
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The answers would be E and F -6 and -3
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4 years ago
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For the function g(x)=3-8(1/4)^2-x
Reika [66]

Using function concepts, it is found that:

  • a) The y-intercept is y = 2.5.
  • b) The horizontal asymptote is x = 3.
  • c) The function is decreasing.
  • d) The domain is (-\infty,\infty) and the range is (-\infty,3).
  • e) The graph is given at the end of the answer.

------------------------------------

The given function is:

g(x) = 3 - 8\left(\frac{1}{4}\right)^{2-x}

------------------------------------

Question a:

The y-intercept is g(0), thus:

g(0) = 3 - 8\left(\frac{1}{4}\right)^{2-0} = 3 - 8\left(\frac{1}{4}\right)^{2} = 3 - \frac{8}{16} = 3 - 0.5 = 2.5

The y-intercept is y = 2.5.

------------------------------------

Question b:

The horizontal asymptote is the limit of the function when x goes to infinity, if it exists.

\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2+\infty} = 3 - 8\left(\frac{1}{4}\right)^{\infty} = 3 - 8\frac{1^{\infty}}{4^{\infty}} = 3 -0 = 3

--------------------------------------------------

\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2-\infty} = 3 - 8\left(\frac{1}{4}\right)^{-\infty} = 3 - 8\times 4^{\infty} = 3 - \infty = -\infty

Thus, the horizontal asymptote is x = 3.

--------------------------------------------------

Question c:

The limit of x going to infinity of the function is negative infinity, which means that the function is decreasing.

--------------------------------------------------

Question d:

  • Exponential function has no restrictions in the domain, so it is all real values, that is (-\infty,\infty).
  • From the limits in item c, the range is: (-\infty,3)

--------------------------------------------------

The sketching of the graph is given appended at the end of this answer.

A similar problem is given at brainly.com/question/16533631

8 0
3 years ago
The interquartile range (IQR) for the<br>data:<br>32,7,3,-5,1,8<br>, 10,36 is :​
GenaCL600 [577]

Answer:

<em>Your Interquartile range (IQR) would be 19.</em>

Step-by-step explanation:

-5, 1, 3, 7, 8, 10, 32, 36

Median: 7.5

Lower quartile: 2

Upper quartile: 21

Interquartile range: 21 - 2 = 19

7 0
3 years ago
I need help can somebody answer them with showing me the work thank you :D
Yuki888 [10]

Question 1. It is graph 3 since the y-intercept in the equation is -2 and the y-intercept on the graph 3 is -2. It is also a quadratic function.

Question 2. It is graph two because the equation listed represents a quadratic function that is positive (graph opens up).

Question 3. It is graph 4 since the y-intercept is 2 and the only graph with that intercept is graph 4. Also, the equation represents a linear function.

Hope this helped :))

3 0
3 years ago
Express the following fractions as the sum or difference of two fractions (x^2+y^2)/x^4
zlopas [31]

Answer:

 \frac{1}{x^2} + \frac{y^2}{x^4}

Step-by-step explanation:

\frac{x^2 + y^2}{x^4} = \frac{x^2}{x^4} + \frac{y^2}{x^4} = \frac{1}{x^2} + \frac{y^2}{x^4}

4 0
3 years ago
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