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swat32
3 years ago
10

Find the volume of the planets

Mathematics
2 answers:
Tamiku [17]3 years ago
7 0
Are you going to insert a picture?
Natalija [7]3 years ago
3 0

Answer:

can you show the planets. or do you want real planets volumes?

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Triangle DEF has side lengths of 8 cm, 10 cm, and 9 cm. Use the relationship between the sides and angles of a triangle to match
Marizza181 [45]

Answer:

Like electric charges repel each other. ... Why can't conductors generate static electricity when rubbed together? They will direct excess charge to earth. Suppose you acquire a positive charge from walking across a carpet.

5 0
3 years ago
Mr. Miles has 7 7/8 pounds of clay to make 3 models. He uses 2 1/10vpounds to make each model. Mr. Miles says he has about 3 pou
Kitty [74]
Answer:
Mr. Miles’s statement is NOT reasonable

Explanation:
If Mr. Miles uses 2 1/10 pounds of clay for each model, Mr. Miles will have used a total of 6.3 pounds of clay.
The decimal form of 7 7/8 is 7.875, so 7.875 minus 6.3 will give you the amount of clay Mr. Miles has left over.

7.875 - 6.3 = 1.575

This means that Mr. Miles statement is not reasonable, as he only has about 1.6 pounds of clay left, not 3.
7 0
3 years ago
Plss plss hurry I need help with number 7
Ymorist [56]

Answer:

the answer is is H hopefully that is right

5 0
3 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

               Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 2.65

           \sigma  = standard deviation = 0.85

            n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

    P(X bar <= 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

8 0
4 years ago
What is the value of the x variable in the solution to the following system of equations? (1 point) 4x + 2y = 6 x − y = 3 −1 5 −
atroni [7]
Equations are: 4x + 2y = 6
x - y = 3
Multiply 2nd equation by 2, 
2x - 2y = 6
Add both the equations,
6x = 12
x = 12/6
x = 2

In short, Your Answer would be 2

Hope this helps!
7 0
3 years ago
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