Plss plss hurry I need help with number 7
1 answer:
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Answer:
By 19% the computer was less than the original price
Step-by-step explanation:
The original price on the computer was $1500
Discount is 25%= 0.25
Discount amount = 1500 * 0.25 = 375
Discounted price = 1500 - 375 = 1125
Now 8% shipping cost to discounted price
8% = 0.08
Shipping cost = 1125 * 0.08 = 90
cost of computer with shipping cost = 1125 + 90 = 1215
Percentage less = (original cost - cost of computer now ) / original cost
=
To get percentage we multiply by 100
0.19 * 100 = 19%
Answer:
The correct answer is
Step-by-step explanation:
To solve the question we note that the question involves a test statistic calculation given by
Where
x₁ = Mean of sample 1
x₂ = Mean of sample 2
n₁ = Sample size of sample 1
n₂ = Sample size of sample 2
s₁ = Variance of sample 1
s₂ = Variance of sample 2
s₁ = ∑(x₁ - x₁')²/n₁, s₂ = ∑(x₂ - x₂')²/n₂
The test statistic is a variable that is derived from a given data sample and is applied in hypothesis testing. The test statistic measures the available data against the expected value from the null hypothesis
With the given data, we have
Refer to the figure shown below.
Because the question states that the semi circles are at the ends of the rectangle, each semicircle has a radius of 30 m.
The circumference of the oval is
2π(30) + 2*120 = 60π + 240 m = 428.5 m
The area of the oval is
π(30²) + 60*120 = 900π + 7200 m² = 1.0027 x 10⁴ m²
Note:
If the semi circles are placed on the 120-m sides of the rectangle, then similar calculations yield:
Circumference = 120π + 120 m = 497 m
Area = 3600π + 7200 m² = 1.851 x 10⁴ m²
Answer:
If the semi circles are placed on the 60-m sides of the rectangle, then
Circumference = 60π + 240 m, or 428.5 m
Area = 900π + 7200 m², or 1.0027 x 10⁴ m²
if the semi circles are placed on the 120-m sides of the rectangle, then
Circumference = 120π + 120 m, or 497 m
Area = 3600π + 7500 m², or 1.851 x 10⁴ m²
Because the question states that the semi circles are at the ends of the rectangle, each semicircle has a radius of 30 m.
The circumference of the oval is
2π(30) + 2*120 = 60π + 240 m = 428.5 m
The area of the oval is
π(30²) + 60*120 = 900π + 7200 m² = 1.0027 x 10⁴ m²
Note:
If the semi circles are placed on the 120-m sides of the rectangle, then similar calculations yield:
Circumference = 120π + 120 m = 497 m
Area = 3600π + 7200 m² = 1.851 x 10⁴ m²
Answer:
If the semi circles are placed on the 60-m sides of the rectangle, then
Circumference = 60π + 240 m, or 428.5 m
Area = 900π + 7200 m², or 1.0027 x 10⁴ m²
if the semi circles are placed on the 120-m sides of the rectangle, then
Circumference = 120π + 120 m, or 497 m
Area = 3600π + 7500 m², or 1.851 x 10⁴ m²