Answer:
by testcrossing with a homozygous recessive partner
Explanation:
<u>If a pet cockroach exists whose zygosity is unknown, this can be determined by a test cross. A test cross involves crossing an organisms whose zygosity is unknown with a partner that is homozygous recessive for the same trait.</u>
Let us assume that brown body is represented by the allele B, the dominant allele. The homozygous recessive version would be bb.
The genotype of a brown cockroach whose zygosity is not known can be denoted as B_, where '_' can be a 'B' or a 'b'.
When B_ is crossed with bb:
B_ x bb
Progeny
2 Bb
2 _b
The phenotype of Bb would be brown (since B is dominant over b) while the phenotype of _b would depend on the zygosity level of the cockroach.
If the unknown genotype is BB, then _b becomes Bb and the phenotype will be a brown body. This means that all the progeny will appear brown. (<em>see the first attached image for the Punnet's square</em>)
In other word, if the unknown genotype is bb, then _b becomes bb and the phenotype will be a alternate color (non-brown) body. This means that 50% of the progeny will appear brown while the remaining 50% will be in the alternate color. (<em>attached</em>
I don’t know the first two but the last one the thousands of subunits are called nucleotides
<span><span>There are choices for this question namely:
A. Its photons have the shortest wavelength in the visual spectrum
B. Its photons have the highest energy in the visual spectrum
C. Its photons have the longest wavelength in the visual spectrum
D. It is not considered a part of the visual spectrum
The correct answer is that </span>its photons have the longest wavelength in the visual spectrum<span>. Chlorophyll, being green in color (around 495 to 590 nm wavelength), reflects this wavelength; not absorbed. Mostly, the chlorophyll absorbs longer wavelengths of light such as red (around 680 nm wavelength) and blue to violet (around 400 to 480 nm wavelnegth). </span></span>
Not always. It just depends on if the traits stay the same
Answer:
At a thermoneutral ambient temperature, cooling either thermode increased oxygen consumption. In a cold environment, cooling either thermode increased the rate of oxygen consumption more than at a thermoneutral temperature. Heating either thermode tended to decrease oxygen consumption in a cold environment. 3.
Explanation: