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4 years ago

What are the answers? No hurry; I just have other things to do.

Mathematics

1 answer:

GalinKa [24]4 years ago

6 0

Answer:

what u need help with

Step-by-step explanation:

You might be interested in

The square of a negative number is twelve more than four times the negative number. Find the number.

Aleks04 [339]

X - the number

$x^2=4x+12 \\
x^2-4x-12=0 \\
x^2-6x+2x-12=0 \\
x(x-6)+2(x-6)=0 \\
(x+2)(x-6)=0 \\
x+2=0 \ \lor \ x-6=0 \\
x=-2 \ \lor \ x=6$

The number is negative, so x=-2.

The number is -2.

3 0

4 years ago

A toddler is allowed to dress himself on Mondays, Wednesdays, and Fridays. For each of his shirt, pants, and shoes, he is equall

avanturin [10]

Answer:

0.0286 = 2.86% probability that today is Monday.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Dressed correctly

Event B: Monday

Probability of being dressed correctly:

100% = 1 out of 4/7(mom dresses).

(0.5)^3 = 0.125 out of 3/7(toddler dresses himself). So

$P(A) = 0.125\frac{3}{7} + \frac{4}{7} = \frac{0.125*3 + 4}{7} = \frac{4.375}{7} = 0.625$

Probability of being dressed correctly and being Monday:

The toddler dresses himself on Monday, so (0.5)^3 = 0.125 probability of him being dressed correctly, 1/7 probability of being Monday, so:

$P(A \cap B) = 0.125\frac{1}{7} = 0.0179$

What is the probability that today is Monday?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0179}{0.625} = 0.0286$

0.0286 = 2.86% probability that today is Monday.

4 0

3 years ago

MATH HELP ASAP!! MARKING BRAINLIEST

olga nikolaevna [1]

Answer:

-1, -7, -13, -19

Step-by-step explanation:

-2(-3)-7 =6-7= -1

-2(0)-7 =0-7= -7

-2(3)-7 =-6-7= -13

-2(6)-7 =-12-7= -19

7 0

3 years ago

Read 2 more answers

The sum of 30 times (1/3)^(n-1) from 1 to infinity

sergeinik [125]

Let

$S_n=\displaystyle1+\frac13+\frac1{3^2}+\cdots+\frac1{3^n}$

Then

$\dfrac13S_n=\displaystyle\frac13+\frac1{3^2}+\frac1{3^3}+\cdots+\frac1{3^{n+1}}$

and

$S_n-\dfrac13S_n=\dfrac23S_n=1-\dfrac1{3^{n+1}}\implies S_n=\dfrac32-\dfrac1{2\cdot3^n}$

and as $n\to\infty$ , we end up with

$\displaystyle\lim_{n\to\infty}S_n=\lim_{n\to\infty}\sum_{i=1}^{n+1}\frac1{3^{i-1}}=\lim_{n\to\infty}\left(\frac32-\frac1{2\cdot3^n}\right)=\frac32$

So we have

$\displaystyle\sum_{n=1}^\infty30\left(\frac13\right)^{n-1}=30\cdot\frac32=45$

8 0

3 years ago

Find the midpoint of BD.

myrzilka [38]

Answer: a/2 a/2

Step-by-step explanation:

same answer for both

8 0

3 years ago

Read 2 more answers