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3 years ago

In a right triangle the lengths of the legs are a and b. Find the length of a hypotenuse, if: a=3, b=4;

Mathematics

2 answers:

prohojiy [21]3 years ago

6 0

Answer:

The hypotenuse is 5

Step-by-step explanation:

We can use the Pythagorean theorem to find the hypotenuse of a right triangle

a^2 +b^2 =c^2 where a and b are the legs and c is the hypotenuse

3^2 +4^2 =c^2

9+16=c^2

25=c^2

Take the square root of each side

sqrt(25) =sqrt(c^2)

5 = c

Lady bird [3.3K]3 years ago

4 0

Answer:

<h3>hypotenuse = 5</h3>

Step-by-step explanation:

Use the Pythagorean theorem:

a² + b² = c²

a, b - legs

c - hypotenuse

We have the lengths of the legs a = 3 and b = 4. Substitute:

c² = 3² + 4²

c² = 9 + 16

c² = 25 → c = √25

c = 5

Pythagorean triple:

3, 4, 5

6, 8, 10

5, 12, 13

and more.

You might be interested in

If a semi circle has a diameter of 5 m what is the area?

klasskru [66]

Answer:

Exact answer = 10.41666666666666666666666666666pi

Estimated answer = 32.70938

Step-by-step explanation:

Semi circle formula: 1/2 * 4/3 * pi * r^3

r = 2.5

1/2 * 4/3 * pi * 2.5^3

2/3 * pi * 2.5^3

2/3 * pi * 15.625

10.416..... * pi

Exact answer = 10.417pi

We can estimate pi as 3.14

So, 10.417 * 3.14 = 32.70938

Exact answer = 10.41666666666666666666666666666pi

Estimated answer = 32.70938

8 0

2 years ago

What is an equation of the line that passes through the points (4,3) and (7,3)

Vika [28.1K]

Answer:

y = 3

Step-by-step explanation:

find out the slope

m = (3-3)/(4-7)

m = 0

so the line is horizontal

passing through the point (x,3)

x can be any value

so the equation is

y = 3

6 0

2 years ago

For the funtion f(x)= (x+7)^5, Find f^-1 (x)

quester [9]

Answer:

The inverse of function $f(x)= (x+7)^5$ is $\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}$

Option A is correct option.

Step-by-step explanation:

For the function $f(x)= (x+7)^5$ , Find $f^{-1} (x)$

For finding inverse of x,

First let:

$y=(x+7)^5$

Now replace x with y and y with x

$x=(y+7)^5$

Now, solve for y

Taking 5th square root on both sides

$\sqrt[5]{x}=\sqrt[5]{(y+7)^5}\\\sqrt[5]{x}=y+7\\=> y+7=\sqrt[5]{x}\\y=\sqrt[5]{x}-7$

Now, replace y with $f^{-1} (x)$

$f^{-1} (x)=\sqrt[5]{x}+7$

So, the inverse of function $f(x)= (x+7)^5$ is $\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}$

Option A is correct option.

6 0

3 years ago

10) Find the area of a circle that has the<br> circumference of 117 cm. Leave it as it.

garik1379 [7]

Step-by-step explanation:

Using the formulas

Solving for

117

≈

1089.33601

cm²

≈

1089.34

cm²

8 0

2 years ago

7. log(x+3)(2x + 3)+log(x+3)(x +5)= 2

OverLord2011 [107]

log(x+3)(2x+3)+log( x+3)( x+5) =2

logx(2x+3)+3(2x+3 )+log x(x+5)+3(x+5)

$log {2x}^{2} + 3x + 6x + 9 + logx {}^{2} + 5x + 3x + 15$

6 0

3 years ago