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3 years ago

EASY QUESTION 100 Points Topic: Multiplying and dividing fractions

Mathematics

2 answers:

Rufina [12.5K]3 years ago

8 0

Answer:

4 times as fast

Step-by-step explanation:

To determine how many time as fast, take the rate up and divide by the rate down

63 minutes

--------------------

15 minute 45 seconds

But we need to be all in the same units so change second to minutes by dividing by 60

63 minutes

--------------------

15 minute 45/60 minutes

63 minutes

--------------------

15.75 minute

4 times

nekit [7.7K]3 years ago

8 0

Answer:

4 times as fast

Step-by-step explanation:

We need to first convert everything to the same units. Let's change it to seconds. There are 60 seconds in a minute, so 63 minutes is 63 * 60 = 3780 seconds and 15 minutes, 45 seconds is 15 * 60 + 45 = 945 seconds.

Now, in order to find how many times as fast the rate going up was than the rate going down was, we divide the ascending rate by the descending rate:

3780 / 945 = 4

The answer is thus 4 times as fast.

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2 years ago

Help! What would d be?

Oxana [17]

Answer:

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Step-by-step explanation:

find the diagonal line passing through the middle of the bottom rectangle:

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find d:

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3 years ago

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Step-by-step explanation:

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2 years ago

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Viefleur [7K]

Answer:

11 games

Step-by-step explanation:

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2 years ago

Read 2 more answers

Comparing Leaking Pool Problem

Blababa [14]

Answer:

Pool 1 leaks faster than pool 2.

Step-by-step explanation:

Rates of change

The rate of change (ROC) is a measure that compares two quantities, usually to know how fast one variable changes in time.

We are given two rates of change for two pools that are leaking. The first one loses 2/3 gallon in 15 minutes, and the other loses 3/4 gallon in 20 minutes.

To compare them, we are required to express time in hours. Recall one hour has 60 minutes, or equivalently, one minute has 1/60 hours. Converting both times, we have:

15 minutes = 15/60 = 1/4 hours

20 minutes = 20/60 = 1/3 hours

Now compute both rates of change:

Pool 1:

$\displaystyle ROC_1=\frac{2/3}{1/4}=\frac{8}{3}\approx 2.67\ gal/h$

Pool 2:

$\displaystyle ROC_2=\frac{3/4}{1/3}=\frac{9}{4}= 2.25\ gal/h$

Comparing both ratios, it's clear pool 1 leaks faster than pool 2.

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3 years ago