Notice that
So
if , and the answer would be C.
BD is a semicircle.
2 answers:
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Let me edit your question to simplify it.
Eureka Math :
A)5 ÷ 1/3= ____.
B) There are ___ thirds in 1 whole.
C) There are ___ thirds in 5 wholes.
D) If 5 of 1/3, what is the whole? ___
E) 3 ÷1/5= ____ .
F) There are ___ fifths in 1 whole.
G) There are ___ fifths in 3 wholes.
H) If 3 of 1/5, what is the whole?___
Answer:
A) 15
B) three thirds
C) 15 wholes
D) whole is 2
E) 15
F) five fifths
G) 15 fifths
H) whole is 1
Step-by-step explanation:
A)
÷
<u>Third:</u>
- third means
<u> </u>
B)
- To make 1 whole from thirds, we need three thirds i.e.
C)
- In 1 whole there are three thirds, so in 5 wholes there are
wholes.
D)
- In
- The whole of
or
is 2 (rounding 1.6 to 2)
E)
÷
<u>Fifth:</u> means
F)
- To make 1 whole of fifths we need five fifths i.e.
G)
- In 1 whole we have 5 fifths, so in 3 wholes we have
fifths
H)
- rounding 0.6 equals to 1
- thus whole is 1.
Answer:
<em>u</em> = 7.21
Step-by-step explanation:
The magnitude of <em>u</em> is just the distance between the two points. The coordinates of the left-most point are (-2,-8) and the coordinates of the right point are (4, -4). I'm assuming the x coordinates here because we don't actually know the scale.
Ok so from these points, you can draw a triangle (u can see it in the attached file).
From the coordinates we can tell the lengths of the sides, and the triangle shows that <em>u</em> is the hypotenuse of the triangle. This triangle is also a right triangle, so u can use Pythagoras' theorem to find the length of <em>u</em>.
Since c = <em>u</em>, we know now that the magnitude of <em>u</em> is 7.21
Hope this helps!
