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2 years ago

Daniel wants to buy cookies for her friends. The area of a cookie is 113.04 in2. What is the circumference of the cookie?

Mathematics

1 answer:

prisoha [69]2 years ago

7 0

Answer:

The circumference of the cookie is 37.68 inches.

Step-by-step explanation:

We have,

The area of a cookie is 113.04 square inches.

It is circular in shape. The area of circle is given by :

$A=\pi r^2$

r is radius of circle

$r=\sqrt{\dfrac{A}{\pi}} \\\\r=\sqrt{\dfrac{113.04}{3.14}} \\\\r=6\ \text{inch}$

The circumference of circular shaped object is given by :

$C=2\pi r\\\\C=2\times 3.14\times 6\\\\C=37.68\ \text{inch}$

So, the circumference of the cookie is 37.68 inches.

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Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

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3 years ago

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2 years ago

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