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3 years ago

Use the Distributive Property to determine which of the following statements is equivalent to 5(6 – 1).

1 answer:

8 0

$\text{You would use the distributive property to get your answer} \\\\\text{This means that you would distribute the 5 to the numbers inside the}\\\text{parenthesis}\\\\\text{When you distribute, you would multiply}\\\\\text{Distribute:}\\\\5(6-1)\\\\5(6)-5(1)\\\\30-5\\\\\text{You would see that this is equal to answer choice C, therefore making}\\\text{C your answer}\\\\\boxed{\text{C). 30 - 5}}$

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Help.. ill give brainliest..

saveliy_v [14]

Answer:

Hi there

1. 28

2. -18

3. -26

4. 14

5. -7

6. 2

7. -17

8. 12

9. -12

10. -15

11. 24

12. 8

13. 2

14. 4

15. - 23

16. - 9

Step-by-step explanation:

there is a easy step to integers

1. if there is a plus then minus or vice versa way then u should subtract .

( + - = - )

2. if there are two plus signs then, add .

( + + = + )

3. if there are two minus signs then , subtract

( - - = - )

hope u understand

5 0

3 years ago

What are the major goals of America's foreign policy?

mafiozo [28]

Answer:

The State Department has four main foreign policy goals: Protect the United States and Americans; Advance democracy, human rights, and other global interests; Promote international understanding of American values and policies

Step-by-step explanation:

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2 years ago

PLEASE HELP!! GEOMETRY SAS ASA AAS

NikAS [45]

Step-by-step explanation:

∆TSU=∆RSU (SAS).

HENCE,

NONe of the above statement is true.

4 0

3 years ago

The linear equation y = 400 + 50x represents the total cost, y , per hour, x , for a lawyer at a law firm. The lawyer charges a

earnstyle [38]

Answer:

453

Step-by-step explanation:

because we multiply the value with the equation

5 0

2 years ago

Please help me with these. These are so hard.<br><br>

LuckyWell [14K]

$\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) ~\hfill a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \boxed{a^6+b^6}\implies a^{2\cdot 3}+b^{2\cdot 3}\implies (a^2)^3+(b^2)^3 \\[2em] [a^2+b^2] [(a^2)^2-a^2b^2+(b^2)^2]\implies \boxed{(a^2+b^2)(a^4-a^2b^2+b^4)}$

about the second one... well, is a "fait accompli" that using the pythagorean theorem, if x = 8 and y = 5, the hypotenuse must be √(8² + 5²) = √(89), which is neither of those choices.

5, 8, 13 are no dice, namely 5² + 8² ≠ 13

25, 64, 17 is are no dice too, because 25² + 17² ≠ 64²

however, 5,12 and 13 are indeed a pythagorean triple

also is 39, 80, 89.

when looking for a pythagorean triple, recall that c² = a² + b².

so the longest leg is the sum of the square of the small ones.

so what you'd do is, check the small legs, square them, add them up, if they're indeed a pythagorean triple, they "must" add up to the longest leg.

4 0

3 years ago