Answer:
60 oz of water to add
45 oz of 35% salt solution should be used
Step-by-step explanation:
Let x = amt no. ounces in the first solution
and 105 - x = amt no. of ounces in the second solution
Ist solution contains 0% salt
2nd solution contains .35(105 - x) salt
.15(105= amt of salt in mix
So.
amt of salt in 1st solution + amt of salt in 2nd solution = amt of salt in the mix
0 + .35(105 - x) = .15(105)
Let's get rid of the fractions by multipying thru the equation by 100
35(105 - x) = 15(105)
3675 - 35x = 1575
-35x = -2100
x = 60 oz of water to add
105 - 60 = 45 oz of 35% salt solution should be used
Answer:
I put in y = 2-x. I believe that was the equation you asked a table for. If it is another equation please tell me or just download or look up Desmos. Desmos helps create graphs and tables. I hope this helps. Have a great rest of your day!
Answer: 28
Step-by-step explanation: Plugging them in, it would be -2 - (-6)(5).
- 2 - (-30)
-2 + 30
28
Answer:
29
Step-by-step explanation: