Answer:
A
Step-by-step explanation:
Answer:
55.563
Step-by-step explanation:
Given the following :
Mean(m) point = 73
Standard deviation( sd) = 10.6
Lower 5% will not get a passing grade (those below the 5% percentile)
For a normal distribution:
The z-score is given by:
z = (X - mean) / standard deviation
5% of the class = 5/100 = 0.05
From the z - table : 0.05 falls into - 1.645 which is equal to the z - score
Substituting this value into the z-score formula to obtain the score(x) which seperates the lower 5%(0.05) from the rest of the class
z = (x - m) / sd
-1.645 = (x - 73) / 10.6
-1 645 * 10.6 = x - 73
-17.437 = x - 73
-17.437 + 73 = x
55.563 = x
Therefore, the score which seperetes the lower 5% from the rest of the class is 55.563
If you Just divided -11u and 44 by -11 u equals 4
Ok so this is a Pythag question...
So the first step would be A squared plus B squared equals C squared
Your A squared would be 12
You do not have B squared value yet
Your C squared Would be 16
So your equation is 12 squared plus B squared equals 16 squared
Simplified that would be 144 plus B squared equals 256
Subtract 144 from both sides and you get 112 equals B squared so do that dividing symbol thing on both sides and you get 10.58 equals c
C= 10.58
