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natta225 [31]
3 years ago
14

Two fair dice are rolled. What is the probability that the first die rolled a 2 and the second die rolled a number greater than

2?
Mathematics
1 answer:
DIA [1.3K]3 years ago
6 0

Answer: first: 1/6   second dice: 4/6

Step-by-step explanation:

So we know that a  dice have the numbers 1,2,3,4,5, and 6 .

So the the probability that first die rolled 2 is 1/6 because there appears only on 2 .

and the probability that the second dice rolled a number greater than 2 is 4/6 or 2/3 because there are 4 numbers greater than 2 out of the 6 total .

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-k+3k combine like terms to create an equivalent expression​
Nimfa-mama [501]

Answer:

2k

Step-by-step explanation:

3k and -k are both like terms, so you can combine them. Adding opposite signs works in the same way as subtraction, so you can rewrite the expression as 3k-k, which is 2k.

8 0
4 years ago
Given V = 1/3pi(r^2)h, solve for r.
Dmitry [639]

Volume = (PI * r^2 * h) / 3

r^2 = (3 * Volume) / (PI * h)

r = Square Root (3 * Volume) / (PI * h)


8 0
3 years ago
Which graph represents the solution to the system of inequalities?
lana [24]

A. hope this helps. Mark as Brainliest.

6 0
4 years ago
Read 2 more answers
A baseball player comes up to bat 3 times during a league game. He either gets a hit or gets an out. How many different combinat
Stella [2.4K]

Answer:

8 different combinations are possible.

Step-by-step explanation:

Here, we have 2 different combinations for each time.

And the player comes out to bat 3 times.

So, total number of combinations are:

2^{3} i.e. a total of 8 number of times.

Let a hit is termed as 'H' and an out is termed as 'O'.

Total combinations are:

{HHH, HHO, HOH, HOO, OHH, OHO, OOH, OOO}

Kindly have a look at the tree diagram attached in the answer area.

In starting, there are 2 combinations possible, i.e. 'O' and 'H'.

After 'O' , 2 possible i.e. 'O' and 'H'.

After 'H' , 2 possible i.e. 'O' and 'H'.

and so on....

8 0
3 years ago
Please help ASAP!!!!!!!!!!
Alexxandr [17]

Value of x is 10

Step-by-step explanation:

  • Step 1: Here, x is the hypotenuse of the right angled triangle. Use the trigonometric ratio cosine to find x.

cos 28° = adjacent side/hypotenuse = 11/x

⇒ x = 11/cos 28° = 11/-0.96 = -11.46 ≈ 10 (rounding off to nearest tenth)

6 0
4 years ago
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