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OlgaM077 [116]
3 years ago
9

I need help ASAP plx

Mathematics
1 answer:
ElenaW [278]3 years ago
7 0

Answer: good thinking

Step-by-step explanation:

here is the answer idk

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3 3/5−1 1/2 subtract
otez555 [7]

Answer:

2 1/10

Steps:

You need both fractions to have the same denominator, you get 6/10 and 5/10

Subtract your fraction:

6/10 - 5/10 = 1/10

Then your whole numbers:

3 - 1 = 2

Then put your answers together:

2 1/10

7 0
3 years ago
Two different 2 digit numbers round to 70 to the nearest 10.The sum of the two numbers is 136.What could the two numbers be?
belka [17]

Answer:

Step-by-step explanation:

If they can be rounded to 70 to the nearest 10s. Then they are from 65 to 74.

Their sum is 136.

If we use 136 divided by 2 we get 68.

Since they're distinct, so one can be 67 and one can be 69

3 0
3 years ago
Solve this .....................​
ycow [4]

Answer:

Step-by-step explanation:  3root5x^2 + 25x - 10root5 = 0

3xroot5 + 25x - 10root5 = 0      [ root x^2 = x]

28x root5 = 10 root5         [ -10root5 turns to 10 root5 when transferred to RHS]

28x root 5/root5 =10

28x=10

x = 10/28

x = 0.35

Hope it helped u,

pls mark as the brainliest

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5 0
3 years ago
Find the distance between the two points. Round to the nearest tenth if necessary. (6, 11), (0, 3) a. 10 b. 14 c. 15 d. 100
lorasvet [3.4K]

Answer: option a

Step-by-step explanation:

You must apply the formula for calculate the distance between the two points. which is shown below:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Therefore, keeping on mind that the points given in the problem are (6, 11), (0, 3), when you substitute values into the formula shown above, you obtain that the distance between these two points is the following:

d=\sqrt{(0-6)^2+(3-11)^2}\\d=10

8 0
3 years ago
Read 2 more answers
SECOND TIME ASKING PLS HELP: A multiple choice question has 3 options. What is the percentage that you will chose the WRONG opti
DiKsa [7]

Answer:

2/3 or 66.67%

Step-by-step explanation:

2 wrong options, 3 total options. 2 over 3.

<em>Big Brain</em>

Hope this helps!! :)

5 0
3 years ago
Read 2 more answers
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