Answer:
B
Step-by-step explanation:
Once you subtract both sides, the 4 is gone then the 10 is subtracted into a 6. You go to the 3x, and just like what you did to the 4 you do the opposite and divide the 3 by itself and the 6 by 3 as well.
Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Step-by-step explanation:
5x=1-6
5x=-5
<h3> x=-1</h3>
-5(-1)-8y=2
5-8y=2
-8y =2-5
-8y=-3
<h3> y=3/8</h3>
Answer:
35 ft
Step-by-step explanation:
Answer:
48-20x=21
Step-by-step explanation:
So, we basically have to clear the fractions (get rid of the denominators)
Multiply everything by the LCM of 6 and 8 (24)
24(2)-24(5/6x)=24(7/8)
48-20x=21
Hope this helps!
