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k0ka [10]
3 years ago
9

Al capitan le venden tela de forma rectangular para hacer otra vela , el lado de menor longitud de la tela seria de 3,3 m y con

toda la tela le alcanzaria para dos velas exactamente. el debe averiguar la longitud de la cuerda que la tensa , antes de cortar la tela pues quiere comprar todo el material al mismo timepo ¿como hallaria las longitudes?¿y cuantos metros tendria cada longitud?
teniendo en cuenta el triangulo con 60,90 y 30 grados
Mathematics
1 answer:
castortr0y [4]3 years ago
6 0
Translate this in English please
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Laura drank 1/3 quart of milk with breakfast, 1/4 quart of milk with lunch, and 1/6 quart of milk with dinner. How much milk did
cluponka [151]

Answer:

9/16 quarts of milk

Step-by-step explanation:

1/3 + 1/4 + 1/6

8/24 + 6/24 + 4/24

18/24 = 9/16 qts.

Your welcome!

Kayden Kohl

8th Grade Student

3 0
3 years ago
What is the distance between 3, 5 and -4, 1
USPshnik [31]

Answer:

Distance = 8.06

Step-by-step explanation:

We have to use the distance formula d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2}  }.

(x_{1},y_{1}) = coordinates of the first point

(x_{2},y_{2} ) = coordinates of the second point

To solve, plug the appropriate values into the formula.

d=\sqrt{(-4-3)^{2} +(1-5)^{2} } = \sqrt{65} = 8.062257748

5 0
3 years ago
6x - 2y = 26<br><br> 2x + 3y = 5<br><br> Solve for X and Y
Softa [21]

Answer:

y is equal to -1

x is equal to 4

Step-by-step explanation:

The first thing you would do is multiply the bottom equation by a negative 3. You will get - 6x - 9y = -15. Keep the top equation the same. Both of the 6x's cancel. You then get -11y = 11 so y is equal to negative 1.

Since you have Y, you can now plug that in to any equation to find the value of x. -6x - 2(-1) = 26. You're left with 4. Plug both of the values into each equation to double check.

7 0
3 years ago
What's the center of a circle whose equation is (x – 14)2 + (y + 21)2 = 64?
kvasek [131]

Answer:

The center of the circle is:

  • \left(a,\:b\right)=\left(14,\:-21\right)

Thus, option (2) is true.

Step-by-step explanation:

The circle equation is given by

\left(x-a\right)^2+\left(y-b\right)^2=r^2

here,

  • r =  raduis
  • center = (a, b)

Given the equation

\left(x-14\right)^2+\left(y+21\right)^2=64

\mathrm{Rewrite}\:\left(x-14\right)^2+\left(y+21\right)^2=64\:\mathrm{in\:the\:form\:of\:the\:standard\:circle\:equation}

\left(x-14\right)^2+\left(y-\left(-21\right)\right)^2=8^2

comparing with the circle equation

\left(x-a\right)^2+\left(y-b\right)^2=r^2

Therefore, the center of the circle is:

  • \left(a,\:b\right)=\left(14,\:-21\right)

Thus, option (2) is true.

7 0
3 years ago
Find the solution of the inequality<br> of b &gt; 11.3
Tems11 [23]
The solution is the interval b is in ]11.3,  infinity[
4 0
3 years ago
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