Answer:
See below ~
Step-by-step explanation:
Given :
⇒ m∠1 = m∠2
⇒ HD = GF
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To Prove :
<u>Δ EHD ≅ Δ EGF</u>
<u />
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Solving :
⇒ m∠1 = m∠2 (Given)
⇒ HD = GF (Given)
⇒ ∠E = ∠E (Common angle)
⇒ ΔEHD ≅ ΔEGF (AAS congruence)
Answer:
The width of the football field is 160 feet.
The length of the football field is 360 feet.
Step-by-step explanation:
Let w represent width of the football field.
We have been given that the length is 200 ft more than the width, so the length of the field would be
.
We are also told that the perimeter is 1,040 ft. We know that football field is in form of rectangle, so perimeter of field would be 1 times the sum of length and width. We can represent this information in an equation as:

Let us solve for w.






Therefore, the width of the football field is 160 feet.
Upon substituting
in expression
, we will get length of field as:

Therefore, the length of the football field is 360 feet.
Answer:
Your answer will be 0.9968
Step-by-step explanation:
Subtract 3,125 to 10 and then divide your answer to 3,125
the function is increasing from x = 0 to x = 1
when x = 0, y = 2
when x = 1, y = 8
this shows an increase of +6, so we know this statement is true
we can see the rest are false simply because they state a decrease when there is an increase. this question is only confusing because we ask you about the increase and decrease in the function, when really its the same thing as asking about an increase or decrease in the y variable.
in other words, all youre looking for is the variation of the value of the y variable that is attached to the specific x variables.
hope this helps!!
Answer:
Step-by-step explanation:
7) The formula for determining the area of a parallelogram is expressed as
Area = base × height.
Length of base = Area/height
Therefore,
Length of base = 7/2 = 3.5 feet
8) The formula for determining the area of a trapezoid is expressed as
Area = 1/2(a + b)h
Where
a and b are the length of the bases
h is the height. Therefore
21 = 1/2(2 + 4)h
21 = 3h
h = 21/3 = 7 inches
9) Area = base × height.
Height = Area/Length of base
Height = 28/14 = 2 inches
10) a and b are 10 inches each.
Area = 1/2(a + b)h
Therefore,
35 = 1/2(10 + 10)h
35 = 10h
h = 35/10
h = 3 inches