Answer:
Option A
Step-by-step explanation:
The standard form of an equation of a circle is represented by the formula 
. Remember that 
is the center and 
is the radius squared.
So, the equation of the circle must be 
. Complete the square to change the form of the equations listed in the options and find the one that is equal.
Let's try this with option A. Move the constants to the right side, then use the completing the square method to place the equation in standard form:
The end result matches with the equation determined before, so option A is the answer.
Given: NQ = NT , QS Bisect NT(∴ NS=ST ) , TV Bisects QN (∴ NV=VQ )
To Prove: QS=TV
Proof: In ΔNQT
NQ=NT
∴ VQ=ST
In a isosceles triangle, If two sides are equal then their opposites angles are equal.
∴ ∠NQT=∠NTQ ( ∵ NQ=NT)
In ΔQST and TVQ
ST=VQ (sides of isosceles triangle)
∠NQT=∠NTQ (Prove above)
QT=TQ (Common)
So, ΔQST ≅ TVQ by SAS congruence property
∴ QS=TV (CPCT)
CPCT: Congruent part of congruence triangles.
Hence Proved
Answer:
Step-by-step explanation:
it doesn't really say what the "face" is, but i'll guess that it's the part marked in yellow? if that's the case then it's just 10 * 10 twice for each of the squares. Really you couldn't see that? :/ 200 is the answer
