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Hitman42 [59]
3 years ago
13

If 1m = 3.3 ft, how many cubic feet is the Kuroshio Sea tank? Volume is 9,450. Show your calculations!

Mathematics
1 answer:
Naddika [18.5K]3 years ago
3 0

Answer:

339604.65 cubic feet

Step-by-step explanation:

We are given that 1 m is equal to 3.3 ft.

1 m = 3.3 ft

This means that if we find the volume of a cube of 1 m, we have its volume as:

1^3 = 1 m^3

In the same way, the volume of a cube of 3.3 ft (1 m) is:

3.3^3 = 35.937 ft^3

This means that:

1m^3 = 35.937 ft^3

The Kuroshio sea tank has volume of 9450 m^3. Its volume in cubic feet is therefore:

1m^3 = 35.937 ft^3\\\\9450 m^3 = 9450 * 35.937 = 339604.65 ft^3

The volume of the tank is 339604.65 cubic feet.

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Troy is building a rectangular garden that is 10 feet by 6 feet. what should be the length of the diagolas to ensure a 90 degree
Maksim231197 [3]
To find the length of the diagonals, Troy should use the Pythagorean Theorem.  The diagonal is going to be the hypotenuse of the triangle (the side directly across from the 90 degree angle).

a^2 + b^2 = c^2
6^2 + 10 ^2 = c^2
136 = c^2; find the square root of 136
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Troy's diagonals are approximately 11.66 feet.
5 0
3 years ago
What is a probability that a person chosen at random who lives in the city live in the east or west region?
Anastasy [175]

<u><em>Answer:</em></u>

0.3

<u><em>Explanation:</em></u>

We are given that:

Probability that a randomly chosen person lives in the East is 0.12

P(East) = 0.12 ..................> I

Probability that a randomly chosen person lives in the West is 0.18

P(West) = 0.18 ............> II

Now, we want to find the probability that the randomly chosen person lives in the East or West

<u>To do this, we will use the following formula:</u>

P(A or B) = P(A) + P(B)

<u>Applying this rule to our givens:</u>

P(East or West) = P(East) + P(West)

P(East or West) = 0.12 + 0.18

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Hope this helps :)

7 0
4 years ago
Read 2 more answers
Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate
yKpoI14uk [10]

Answer:

a) 0.5588

b) 0.9984

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24

Standard Deviation, σ = 6.4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}        

a) P(score between 20 and 30)

P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{6.4} \leq z \leq \displaystyle\frac{30-24}{6.4}) = P(-0.62 \leq z \leq 0.94)\\\\= P(z \leq 0.94) - P(z < -0.62)\\= 0.8264 - 0.2676 = 0.5588 = 55.88\%

P(20 \leq x \leq 30) = 55.88\%

b) Sampling distribution

Sample size, n = 22

The sample will follow a normal distribution with mean 24 and standard deviation,

s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{6.4}{\sqrt{22}} =1.36

c) P(mean score of sample is between 20 and 30)

P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{1.36} \leq z \leq \displaystyle\frac{30-24}{1.36}) = P(-2.94 \leq z \leq 4.41)\\\\= P(z \leq 4.41) - P(z < -2.94)\\= 1 - 0.0016 = 0.9984 = 99.84\%

P(20 \leq x \leq 30) =99.84\%

5 0
4 years ago
In January, you deposit $150 into your checking account. Every month after that, you deposit 10% more than you did the month bef
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