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3 years ago

A hole the size of a photograph is cut from a red piece of paper to use in a picture frame.

Mathematics

2 answers:

dolphi86 [110]3 years ago

8 0

Answer:

Its D

Step-by-step explanation:

Just took the quiz

mario62 [17]3 years ago

6 0

Answer:

D. 47 square units

Step-by-step explanation:

The area of the piece of red paper after the hole for the photograph has been cut is the difference between the area of large square and are of small square.

Area of large square:

The length of the side of large square is

$EF=|-4-4|=8\ units$

Area of large square $=8^2=64\ un^2.$

Area of small square:

The length of the side of large square is

$AB=\sqrt{(-3-(-2))^2+(-2-2)^2}=\sqrt{(-1)^2+(-4)^2}=\sqrt{1+16}=\sqrt{17}\ units$

Area of small square $=\sqrt{17}^2=17\ un^2.$

Difference:

$64 \ un^2-17\ un^2=47\ un^2$

You might be interested in

(Look at picture above) Find the volume of the cone. Round your answer to the nearest tenth. 9 yd 7 yd The volume of the cone is

nata0808 [166]

Answer:

V = 115.5 cubic yards

Step-by-step explanation:

V (cone) = 1/3πr²h

just substitute given values to get:

r = 7/2 or 3.5

h = 9

V = π(3.5²)(9)/3

V = 115.5 cubic yards

3 0

2 years ago

The arc length of a sector created by a 90° angle is 25 cm. What is the circumference of the entire circle? Express

docker41 [41]

Answer:

We know length of one quarter of a circle = 2πr/4 = πr/2

So here we can make the equation for to find thr value of radius r

length of one quarter given = 25 cm

so πr/2 = 25 cm

=> πr = 50 cm

=> r = 50/π cm

So the entire circumference of circle =

2πr

= 2 π 50/π cm

= 100π/π cm (ans)

Here we dont substitute the value of π due to represent the answer in terms of pi.

Hope it helps you

6 0

2 years ago

What is 1.53 to the nearest tenth

Marat540 [252]

1.53 rounded to the nearest tenth is 1.5

7 0

3 years ago

Read 2 more answers

Solve the following equations;- x - 9 /√x + 3 =1

fgiga [73]

Answer:

13 , 6.

Step-by-step explanation:

A equation is given to us and we need to find out the value of x . The given equation to us is ,

$\sf\implies \dfrac{ x -9}{\sqrt{x+3}}= 1$

Cross multiply ,

$\sf\implies x - 9 =\sqrt{ x +3}$

Squaring both sides ,

$\sf\implies (x - 9)^2 = x + 3$

Simplify the whole square ,

$\sf\implies x^2+9^2-2.9.x = x +3 \\$

$\sf\implies x^2+81 - 18x = x -3$

Add 3 and subtract x on both sides ,

$\sf\implies x^2 -18x-x +81-3=0$

Simplify ,

$\sf\implies x^2 -19x +78=0$

Split the middle term of the quadratic equation,

$\sf\implies x^2-13x-6x+78=0$

Take out common ,

$\sf\implies x( x -13)-6(x-13)=0$

Take out ( x -13 ) as common ,

$\sf\implies ( x -13)(x-6)=0$

Equate both factors to 0 ,

$\sf\implies \boxed{\pink{\sf x = 13,6}}$

Hence the value of x is 13 or 6 .

7 0

2 years ago

Willie and anjali each improved their yards by planting daylilies and ivy. They bought their supplies from the same store. Willi

Fiesta28 [93]

Answer:the cost of one day lily = $9 and cost of one pot of ivy = $2

Step-by-step explanation:

Step 1

let day lilies be rep as d

and ivy be represented as i

So that The expression for what Willie spent on 12 day lilies and 4 pots of ivy = $116 be

12 d+ 4i = 116 ---- equation 1

and for Anjali spending $60 on 6 day lilies and 3 pots of ivy be

6d+ 3i = $60------ equation 2

Step 2 --- Solving

12 d+ 4i = 116 ---- equation 1

6d+ 3i = $60------ equation 2

Multiply equation 2 by (2) and subtracting equation 1 from it

12d+ 6i= 120

--12 d+ 4i = 116

2 i= 4

i = 4/2 = 2

TO find d, putting the value of i = 2 in equation 1 and solving

12d+ 4(2) = 116

12d= 116-8

12d= 108

d= 108/12= 9

Therefore the cost of one day lily = $9 and cost of one pot of ivy = $2

5 0

3 years ago