Answer:
P(X= k) = (1-p)^k-1.p
Step-by-step explanation:
Given that the number of trials is
N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.
Given p = success,
1 - p = failure
Hence the distribution is described as: Pr ( FFFF.....FS)
Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p
Pr((X=k) = (1 - p)^ (k-1) .p
Since N<=k
Pr (X =k) = p(1-p)^k-1, k= 1,2,...k
0, elsewhere
If the probability is defined for Y, the number of failure before a success
Pr (Y= k) = p(1-p)^y......k= 0,1,2,3
0, elsewhere.
Given p= 0.2, k= 3,
P(X= 3) =( 0.2) × (1 - 0.2)²
P(X=3) = 0.128
Answer:
$80
Step-by-step explanation:
4x/2=2x
7x-60
7x-60=2x*2
7x-60=4x
3x=60
x=20
20*4=80
Answer:
0.336 or 33.6%
Step-by-step explanation:
It follows from the question that the probability of a complaint is 35% = 35/100 = 0.35. Let's call this probability, p.
The probability of no complaint is mutually exclusive of p since both are complements. Let's call this q. Then
q = 1 - p = 1 - 0.35 = 0.65
The distribution is a binomial distribution.
Events of each call are independent.
The probability of 2 calls with complaint out of 5 is
Answer:
62.28
Step-by-step explanation:
If the smaller volume ratio is 4 to 1331, divide 1331 by 4 to get the multiplying factor.
1331/4 = 332.75
Now we multiply 332.75 by 7 to get our larger volume.
332.75 x 7 = 2329.25
2,329 is our larger volume.
I hope this helps!
