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3 years ago

1. Evan does some shopping at a market.

Mathematics

1 answer:

miskamm [114]3 years ago

6 0

Answer:

4.14

Step-by-step explanation:

the orange is 1 pound

the green is 0.1 pound

the blue is 0.01 pound

3 orange is 3

11 green is 1.1

4 blue is 0.04

3+1.1+0.04=4.14

hope that made sense

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Help me please ASAP<br> !!!!!

OLEGan [10]

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Step-by-step explanation:

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3 years ago

What expression is equivalent to 2( 4g+6h+7)

SIZIF [17.4K]

Answer:

= 8g + 12h + 14

Step-by-step explanation:

2( 4g+6h+7)

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3 years ago

F(x) = 9 sin(x) + cot(x), −π ≤ x ≤ π find the interval of increase.

podryga [215]

We are given the function
F(x) = 9 sinx + cot x

We need to take the first derivative of the given function so,
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x = 2.04

Picking out an arbitrary value between 2.04 and π, say 3 and substituting in F(x)
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Therefore, the interval where the function is increasing is from 2.04 to π
Consequently, the interval where the function is decreasing is from -π to 2.04<span />

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4 years ago

The written portion of bens driving test had 40 questions Ben correctly answered 12 more questions than he missed how many quest

lilavasa [31]

We wil name x to the amount of correctly answered questions. Then, we get:

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1 year ago

Find the derivatives of the following implicit function

ddd [48]

Answer:

$\frac{d}{dx}\left(y\right)=\frac{2-6x+6y}{-6x+2y+1}$

Step-by-step explanation:

$3x^2-6xy+y^2=2x-y\\\mathrm{Treat\:}y\mathrm{\:as\:}y\left(x\right)\\\mathrm{Differentiate\:both\:sides\:of\:the\:equation\:with\:respect\:to\:}x\\\frac{d}{dx}\left(3x^2-6xy+y^2\right)=\frac{d}{dx}\left(2x-y\right)\\\frac{d}{dx}\left(3x^2-6xy+y^2\right)=6x-6\left(y+x\frac{d}{dx}\left(y\right)\right)+2y\frac{d}{dx}\left(y\right)\\\frac{d}{dx}\left(2x-y\right)=2-\frac{d}{dx}\left(y\right)\\6x-6\left(y+x\frac{d}{dx}\left(y\right)\right)+2y\frac{d}{dx}\left(y\right)=2-\frac{d}{dx}\left(y\right)$

$\mathrm{For\:convenience,\:write\:}\frac{d}{dx}\left(y\right)\mathrm{\:as\:}y^{'\:}\\6x-6\left(y+xy^{'\:}\right)+2yy^{'\:}=2-y^{'\:}\\\mathrm{Isolate}\:y^{'\:}:\quad y^{'\:}=\frac{2-6x+6y}{-6x+2y+1}\\y^{'\:}=\frac{2-6x+6y}{-6x+2y+1}\\\mathrm{Write}\:y^{'\:}\:\mathrm{as}\:\frac{d}{dx}\left(y\right)\\\frac{d}{dx}\left(y\right)=\frac{2-6x+6y}{-6x+2y+1}$

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3 years ago