Answer:
A
Step-by-step explanation:
took test
month 4: 13.25*4=53. 53+50 = 103
month 4: 25.75*4 = 103
They both cost $103 on month 4
Answer:
Length = 2x+y cm and since it's a rectangle,
2x+y=3x-y ---------------- (i)
width = 2x-3 cm
It's perimeter,
2(2x+y+2x-3)=120 ---------------- (ii)
Solving both equations,
x = 14 cm
y = 7 cm
so length is, 2×14+7 = 35 cm
and width is, 2×14-3 = 25 cm
so area will be, 35×25 = 875 cm²
Answered by GAUTHMATH
Since we are given a point that lies on the line, the logical first step would be to plug that point in. If we plug that point in, we are left with no variables in the equation other than p. So:
X^2 - 6x + 9 = -1 + 9. We need to solve for x.
First, add one on each side of the equation:
x^2 - 6x + 9 + 1 = -1 + 9 + 1
x^2 - 6x + 10 = 9
Then subtract 9 from each side:
x^2 - 6x + 10 - 9 = 9-9
x^2 - 6x + 1 = 0
Now we got an equation = 0. This an equation from the second degree, it represented by a parabola which turns up since a>0.
This equation is the developed form as ax^2 + bx + c with a=1; b = -6; and c=1.
Now, to find the zeroes of this equation, we need to find delta Δ.
Δ = b^2 - 4ac.
If Δ>0, the equation admits 2 zeroes: x=(-b-√Δ)/2a and x = (-b+√Δ)/2a.
If Δ<0, the equation doesn't admits any zero.
If Δ=0, the equation admits one zero x = -b/2a
Δ = (-6)^2 - 4(1)(1)
Δ = 36 - 4
Δ = 32
Δ>0
So the zeroes of the equation are:
x = (-b-√Δ)/2a = (6-4√2)/2
x = (-b+√Δ)/2a = (6+4√2)/2
Hope this Helps! :)
