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2 years ago

Genuinely don’t know how to do geometry.

Mathematics

1 answer:

bazaltina [42]2 years ago

4 0

Answer:

Im sorry for you this is too complex

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Bill reads 1/5 of a book on Monday he reads 2/3 of a book on Tuesday if he finish reading the book on Wednesday what fraction of

Evgen [1.6K]

total book =1

1/5 + 2/3 + wed = 1

get a common denominator of 15

1/5 * 3/3 + 2/3 * 5/5 + wed = 1 * 15/15

3/15 + 10/15 + wed = 15/15

combine like terms

13/15 + wed = 15/15

subtract 13/15 on each side

wed = 15/15-13/15

wed = 2/15

He read 2/15 of the book on Wednesday

5 0

3 years ago

Janet drove 420 miles in 6 hours. What was her constant rate of change? Pls answer

Ira Lisetskai [31]

Answer:

70 miles per hour

Step-by-step explanation:

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2 years ago

Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.

Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

Step 1

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

Step 2

Using the distance formula

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given E(-2,3), F(1,6)

$|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given F(1,6), G(4,3)

$|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given G(4,3), H(1,0)

$|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}$

Given E (−2, 3), H (1, 0)

$|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}$

Step 3

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|= $\frac{6-3}{1+2} =\frac{3}{3}=1$

Segment GH, G (4, 3), H (1, 0)

Slope of |GH| $= \frac{0-3}{1-4} =\frac{-3}{-3}=1$

Step 4

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH| $= \frac{0-3}{1+2} =\frac{-3}{3}=-1$

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| $=\frac{3-6}{4-1} =\frac{-3}{3}=-1$

Step 5

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

Step 6

Segment EF, segment FG, segment GH, and segment EH are congruent.

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

Step 7

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

4 0

3 years ago

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What happened to the tutor option :(

ElenaW [278]

Answer: wym

Step-by-step explanation:

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2 years ago

Why there must be at least two lines on any given plane

Elanso [62]

Part of tue reason is to balance the plane so you arent flying sideways.. :D not many happy people on a sideways plane ;) I am an idiot haha oh welp go ahead and delete it haha

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2 years ago

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