The ___ of an angle is the ratio of the opposite leg length to the hypotenus length.

Mathematics

2 answers:

White raven [17]3 years ago

5 0

Answer:

hi! your answer should be B. sine!

Step-by-step explanation:

use soh cah toa!

soh- Sine times Opposite over Hypotenuse of angle a

cah- Cosine times Adjacent over Hypotenuse of angle a

toa- Tangent times Opposite over Adjacent of angle a

hope this helps! good luck :)

Ivanshal [37]3 years ago

4 0

Answer:

Step-by-step explanation:

Tangent Maybe?

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The latter is leaning against the building so that the distance from the ground to the top of the ladder is 9 feet less than the

Rama09 [41]

Complete question :

The latter is leaning against the building so that the distance from the ground to the top of the ladder is 9 feet less than the length of the ladder finally put the ladder in the distance from the bottom of the ladder to the building 15 feet. Find length of the ladder.

Answer:

Step-by-step explanation:

From Pythagoras :

Hypotenus = sqrt(opposite² + adjacent²)

From the diagram

l = sqrt((l-9)² + 15²)

l² = (l² - 18x + 81 + 225)

Square both sides

l² = l² - 18x + 306

l² - l² = 306 - 18x

18l = 306

l = 306/18

l = 17

3 0

3 years ago

In circle pp, ad¯¯¯¯¯ad¯ is a diameter and bc¯¯¯¯¯bc¯ is perpendicular to ad¯¯¯¯¯ad¯ at ee. if pd=7pd=7 and ae=4ae=4, find cece.

kvv77 [185]

See the attached figure.

<span>ad is a diameter of the circle with center p
</span>
∵ pd = radius = 7 ⇒⇒⇒ ∴ ad = 2 * radius = 2 * 7 = 14
∵ ae = 4 ⇒⇒⇒ ∴ ed = ad - ae = 14 - 4 = 10
∵ ad is a diameter
Δ acd is a triangle drawn in a half circle
∴ Δ acd is a right triangle at c
∵ bc ⊥ ad at point e
By applying euclid's theorem inside Δ acd
∴ ce² = ae * ed
∴ ce² = 4 * 10 = 40
∴ ce = √40 = 2√10 ≈ 6.325