- 3x+y=8--(1)
2x+4y=12
- x+2y=6--(2)
- (1)×1 and (2)×3
Subtract both
Put the value in eq(2)
How many unique triangles can be drawn with side lengths of 3 units, 4 units, and 5 units
1 answer:
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Answer:
radius = 5 in
Step-by-step explanation:
Using the formula for calculating the area (A) of a circle
A = πr² ( r is the radius )
here A = 78.5, hence
3.14r² = 78.5 ( divide both sides by 3.14 )
r² = = 25 ( take the square root of both sides )
r = = 5