Please help asap, shehhrhd
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Combinations = n! / (n - r)! r!
In this case:
n = 4
r = 3
Combinations = 4! /(4-3)! 3! = 24/(1)(6) = 24/6 = 4
Answer:
4 arrangements
Move the constant to the right-hand side and change its sign to minus sign since it is in plus
Subtract the numbers
Divide both sides of equation by 3
- On observing the above steps, Option B is correct!
- <em>First</em><em> </em><em>step</em><em> </em><em>is</em><em> </em><em>subtraction</em><em> </em><em>then</em><em> </em><em>division</em>
Answer:
Step-by-step explanation:
<u>Step 1: Divide</u>
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