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artcher [175]
3 years ago
7

Evaluating express 6 Evaluate 13 + - when y = 6. y

Mathematics
1 answer:
Step2247 [10]3 years ago
7 0

Step-by-step explanation:

how i think this question is

13+ -y

y=6

= 13 + -6

=7

therefore the answer is 7

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1/6 + 2/3 tell me wat it is pls​
Nutka1998 [239]

Answer: 5/6

Step-by-step explanation:

2/3=4/6

1/6 + 4/6 = 5/6

5 0
3 years ago
Read 2 more answers
please help! I missed one day of class in algebra and missed learning this so I'm really confused! if someone could help me that
Kipish [7]
Perpendicular means it’s opposite reciprocals for example : the slope is 2 then the perpendicular line’s slope would be -1/2 because it flips the number also makes it the opposite sign.

If it’s parallel then the slope would be the same

I hope that helps
7 0
3 years ago
Which is an equation for the circle with a center at (-2, 3) and a radius of 3?
kkurt [141]

Answer:

(x+2)^2 +(y-3)^2 = 9

Step-by-step explanation:

(x-h)^2 +(y-k)^2 = r^2

Where (h, k) is the center of the circle

And r is the radius of the circle.

Hope this helps.

6 0
3 years ago
Consider the equation 4x + 1 = 2x + 5
Darya [45]

(a) Without solving the equation we can't determine whether its true or false.

(b) If x = 3

4x + 1 = 2x + 5

4(3) + 1 = 2(3) + 5

12 + 1 = 15 + 5

13 = 20

No, if x = 3, the equation will not be true.

(c) 4x + 1 = 2x + 5

4x - 2x = 5 - 1

2x = 4

x = 4/2

x = 2

This shows that x = 2 makes the equation true.

8 0
3 years ago
From a random sample of 41 teens, it is found that on average they spend 43.1 hours each week online with a population standard
Nadusha1986 [10]

Answer:

Step-by-step explanation:

We want to determine a 90% confidence interval for the mean amount of time that teens spend online each week.

Number of sample, n = 41

Mean, u = 43.1 hours

Standard deviation, s = 5.91 hours

For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean +/- z ×standard deviation/√n

It becomes

43.1 ± 1.645 × 5.91/√41

= 43.1 ± 1.645 × 0.923

= 43.1 ± 1.52

The lower end of the confidence interval is 43.1 - 1.52 =41.58

The upper end of the confidence interval is 43.1 + 1.52 =44.62

Therefore, with 90% confidence interval, the mean amount of time that teens spend online each week is between 41.58 and 44.62

8 0
3 years ago
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