if you’re good with set theory in math 30 please help with questions 31 and 32!! real answers only !!

Mathematics

1 answer:

GREYUIT [131]3 years ago

7 0

Answer: 31) d 32) c

Step-by-step explanation:

31)

A = {1, 3, 5, 15}

B = {2, 3, 5, 7}

A ∪ B = {1, 2, 3, 5, 7, 15}

C = {2, 4, 6, 8}

(A ∪ B) ∩ C = {1, 2, 3, 5, 7, 15} ∩ {2, 4, 6, 8} = {2}

2 is the only number in both sets

32)

The pattern is: reflection, add symbol, ..., reflection, add symbol.

The last image shown is: add symbol

So the next image will be: reflection (flipped to the left)

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Inequation 1:

$\frac{2}{3}x-3 \geq y$

to plot the pairs (x, y) for which the inequation holds, draw the line $y=\frac{2}{3}x-3$

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2:

$y+ \frac{2}{3}x\ \textless \ 4$

$y\ \textless \ - \frac{2}{3} x+ 4
$

draw the lines

i) $y=\frac{2}{3}x-3$ use points (0, -3), (3, -1)

ii) $y=- \frac{2}{3} x+ 4$ use points ( 0, 4), (3, 2)

let's use the point P(3, 3) to see what region of the lines need to be coloured:

$\frac{2}{3}x-3 \geq y$ ;
$\frac{2}{3}(3)-3 \geq 3$
$2-3 \geq 3$ , not true so we color the region not containing this point

$y+ \frac{2}{3}x\ \textless \ 4$
$(3)+ \frac{2}{3}(3)\ \textless \ 4$
$3+ 5\ \textless \ 4$ not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.