Question

What is the lateral surface area of the square pyramid below?

Answer 1

Answer:

$=4(\dfrac{1}{2}\times Base \times Height )\\\\=4(\dfrac{1}{2} \times 3 \times 8 )\\\\=4(\dfrac{1}{2} \times 24 )\\\\=4 \times 12\\\\=48\,\,inch^2$

Therefore, Lateral surface area of the pyramid= $48\,\,inch^2$

Step-by-step explanation:

The lateral surface area of the pyramid is the area of the all of its four triangular faces, excluding base :

Area of a triangle is:

$=\dfrac{1}{2} \times Base \times Height$

Base= 3 inches

Height=8 inches

Lateral surface area of the pyramid:  

$=4(\dfrac{1}{2}\times Base \times Height )\\\\=4(\dfrac{1}{2} \times 3 \times 8 )\\\\=4(\dfrac{1}{2} \times 24 )\\\\=4 \times 12\\\\=48\,\,inch^2$

Therefore, Lateral surface area of the pyramid= $48\,\,inch^2$