Answer: 1.5
Step-by-step explanation:
2.1/1.4=1.5
(L=17m and W=20m) and (L=40m and W=8.5m) are the possible dimensions (length and width) of the field given that the three sided fence has a length of 57m the area of the land is 340 square meters. This can be obtained by forming quadratic equation for the data.
<h3>Calculate the set of possible dimensions (length and width) of the field:</h3>
Let length be L and width be W.
Given that,
three sided fence has a length of 57m,
⇒ 2W + L = 57 m ⇒ L = 57 - 2W
the area of the land is 340 square meters
length × width = 340 ⇒ L × W = 340
(57 - 2W)W = 340
57W - 2W² = 340
2W² - 57W + 340 = 0
Solve for W using quadratic formula,
a = 2, b = -57, c = 340
W = (-b±√b²-4ac)/2a
= (57±√3249-2720)/4
= (57±√529)/4
= (57±23)/4
W = 20 m and W = 8.5 m
For W=20, L=57-2(20) = 17
For W=8.5, L=57-2(8.5) = 40
Hence (L=17m and W=20m) and (L=40m and W=8.5m) are the possible dimensions (length and width) of the field given that the three sided fence has a length of 57m the area of the land is 340 square meters.
Learn more about quadratic equations:
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Answer:
5
Step-by-step explanation:
cross multiply
isolate x
12x=7.5(8)
12x=60
12x/12=60/12
5 is the answer
Answer: 16
Step-by-step explanation: we will do PEMDAS for this. first 6-3= 3 this makes the equation 4+8/2*3
next, 8/2 because of pemdas. this is 4. this makes the equation 4+4*3. nest do 4*3. this is 12. then just add 4 to make 16.
