2 years ago

Find the solution for -3x - 5 = 10 “help me please

Mathematics

1 answer:

s344n2d4d5 [400]2 years ago

5 0

-3× - 5= 10+5

-3×=15

15÷-3 = -5

x= -5

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Joel made egg sandwiches and tuna sandwiches in the ratio 2:3. He then made 15 more tuna sandwiches and the ratio changed to 1:3

Ksenya-84 [330]

So 2e:3t 3t+15=1e:3e so

2e:3t
3t+15
1e:3t
1e:3t=2e:6t
so 2e:6e
2e:3t+15=2e:6t
15=3t
t=5
2+3=5 units
5 times 5=25
he made 25 samiches in all
check
e:t=10:15=2:3
15+15=30
10:30=1:3
checks

he made 25 sammiches origonaly

8 0

2 years ago

2 If A= 4 3 find A1 using elementary row operations.

MA_775_DIABLO [31]

Answer: $A^{-1}=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]$

Step-by-step explanation:

$\left[\begin{array}{cc}2&1\\4&3\end{array}\right]=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]$

$\dfrac{1}{2}Row\ 1\rightarrow\left[\begin{array}{cc}1&\frac{1}{2}\\4&3\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\0&1\end{array}\right]$

$Row\ 2 -4 \ Row\ 1\rightarrow \left[\begin{array}{cc}1&\frac{1}{2}\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\-2&1\end{array}\right]$

$Row\ 1-\dfrac{1}{2}\ Row\ 2 \rightarrow \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]$