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3 years ago

A system of equations is shown below.

1 answer:

5 0

-3x + 7y = -16 . . . (1)
-9x + 5y = 16 . . . .(2)

(1) x 3 => -9x + 21y = -48 . . . (3)
(2) - (3) => -16y = 64 . . . (4)

Required equivalent system of equations is
-9x + 5y = 16
-16y = 64

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(3) The difference between two numbers is 8. If the larger is

Alecsey [184]

Answer:

x= 62

y= 54

Step-by-step explanation:

Step one:

given data

let the numbers be x and y and the larger be x the smaller be y

The difference between two numbers is 8

x-y= 8-----------1

If the larger is subtracted from three times the smaller, the difference is 100

3y-x=100------------2

from eqn 1, x= 8+y

put this in eqn 2

3y-(8+y)=100

3y-8-y=100

collect liker terms

3y-y-8=100

2y=108

y= 54

put y= 54 in eqn 1

x-y=8

x-54= 8

x= 8+54

x=62

5 0

3 years ago

Pls help me do this :']

JulijaS [17]

Answer:

ur mom

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

HELP ASAP!!

garri49 [273]

I'm pretty sure it would be x - y + 1 = 0 because if you plug in one of the coordinates into each equation, this is the only one that works.

y - x + 1 = 0
2 - 1 + 1 = 0
2 = 0 not correct

x - y + 1 = 0
1 - 2 + 1 = 0
0 = 0 correct

-x - y + 1 = 0
-1 - 2 + 1 = 0
-2 = 0 not correct

4 0

3 years ago

A pharmaceutical company receives large shipments of aspirin tablets. The acceptance sampling plan is to randomly select and tes

Anvisha [2.4K]

Answer:

Probability will be 0.5779

Step-by-step explanation:

Number of tablets n = 19

Probability of defect rems that is p = 0.03

Here number of trials is fixed and probability of success = 0.03

Here p = 0.03

So q = 1 - p = 1 -0.03 = 0.97

By using binomial distribution

Probability is given by $^nC_rp^rq^{n-r}$

So P(0 or 1) = $^{19}C_0{0.03}^0{0.97}^{19-0}+^{19}C_1{0.03}^1{0.97}^{19-1}=0.5606+0.0173=0.5779$

4 0

3 years ago

A dog breeder would like to know how many Dalmatian puppies are typically born in a litter. He conducts some research and select

podryga [215]

Answer:

c. 6.2 ± 2.626(0.21)

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 101 - 1 = 100

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.995$ . So we have T = 2.626