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Temka [501]
3 years ago
15

A system of equations is shown below.

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
5 0
-3x + 7y = -16 . . . (1)
-9x + 5y = 16 . . . .(2)

(1) x 3 => -9x + 21y = -48 . . . (3)
(2) - (3) => -16y = 64 . . . (4)

Required equivalent system of equations is
-9x + 5y = 16
-16y = 64
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A diameter of a circle has endpoints P(-10,-2) and Q(4,6).
Lesechka [4]

Check the picture below.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ P(\stackrel{x_1}{-10}~,~\stackrel{y_1}{-2})\qquad Q(\stackrel{x_2}{4}~,~\stackrel{y_2}{6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{4-10}{2}~~,~~\cfrac{6-2}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{4}{2} \right)\implies \stackrel{\textit{center}}{(-3~,~2)} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{\textit{center}}{(\stackrel{x_1}{-3}~,~\stackrel{y_1}{2})}\qquad Q(\stackrel{x_2}{4}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{[4-(-3)]^2+[6-2]^2}\implies r=\sqrt{(4+3)^2+(6-2)^2} \\\\\\ r=\sqrt{49+16}\implies r=\sqrt{65} \\\\[-0.35em] ~\dotfill

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{2}{ k})\qquad \qquad radius=\stackrel{\sqrt{65}}{ r} \\[2em] [x-(-3)]^2+[y-2]^2=(\sqrt{65})^2\implies (x+3)^2+(y-2)^2=65

5 0
3 years ago
Simplify the following expression 4(8x + 3y)​
netineya [11]

Step-by-step explanation:

4(8x + 3y)

= 4 × 8x + 4 × 3y. [Gets multiplied with 4]

= <u>32x + 12y (Ans)</u>

4 0
3 years ago
The long jump distances of four students are listed in the table below. How much farther
Fiesta28 [93]

Joe jumped the farthest at 6 1/4 (6 ft 3 in)

Chelsey jumped the shortest ar 4 1/5 (4 ft 2.4 in)

6-4=2

3-2.4=.6

the difference is: 2 ft and 0.6 in

4 0
3 years ago
A car that sold for $11,900 has a sales tax of $767. How
dlinn [17]

Answer: 9,953

Step-by-step explanation:

The first step is to find what the sales tax rate is for the first car because it will be the same for the second.

11,900/767 = .064

Now to find the cost of the second car we divide.

637/.064 = 9,953.125 Round to nearest dollar.

4 0
2 years ago
Recall that the primes fall into three categories: Let Pi be the set of
a_sh-v [17]

Answer:

Check the explanation

Step-by-step explanation:

(a)Let p be the smallest prime divisor of (n!)^2+1 if p<=n then p|n! Hence p can not divide (n!)^2+1. Hence p>n

(b) (n!)^2=-1 mod p now by format theorem (n!)^(p-1)= 1 mod p ( as p doesn't divide (n!)^2)

Hence (-1)^(p-1)/2= 1 mod p hence [ as p-1/2 is an integer] and hence( p-1)/2 is even number hence p is of the form 4k+1

(C) now let p be the largest prime of the form 4k+1 consider x= (p!)^2+1 . Let q be the smallest prime dividing x . By the previous exercises q> p and q is also of the form 4k+1 hence contradiction. Hence P_1 is infinite

4 0
3 years ago
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