Let
be the number of students who eat cauliflower.
Therefore,
.
Let
be the total number of students surveyed.
Therefore, 
Thus, 

Now, for 90% confidence level, from the table we know that
.
The formula for the interval range of proportion of students is :

Plugging in the values we get:

Thus, Jane is 90% confident that the population proportion p, for students who eat cauliflower in her campus is between 5.398% and 15.114% (after converting the answer we got to percentage).
Answer:(x)=10^x
Step-by-step explanation:
Log(x)=x
(x)=10^x
Do 50 multiplied by x = 8. Solve for x.
It would give you .16 which is 16%.
Answer:
A.
Step-by-step explanation:
Yes, because the critical value method uses critical value(s) to identify the rejection region(s). The P-value method compares the P-value with the level of significance alpha.
Explanation: When you reduce your significance value, the critical value either gets smaller, or larger depending on the tails. This means that your test statistic would also have to get smaller or larger depending on the tail in order to reject the null hypothesis.
At test that rejected the null hypothesis at 5% may not reject it at 1%
The slope of a line in form ax+by=c is -a/b
the yint of the line is c/b
so
-6x-5y=15
slope=-(-6)/-5=6/-5=-6/5
yint is 15/-5=-15/5=-3
slope=-6/5
yint is -3
or you could just do slope intercept and solve for y
y=mx+b
m=slope
b=yintercept
slope=-6/5
yint is -3