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andreyandreev [35.5K]

4 years ago

7

Please solve this ASAP! I WILL GIVE 20 points!

1 answer:

Bond [772]4 years ago

3 0

Answer:

15 parts

Step-by-step explanation:

Sugar: 20/4=5 you are doing five times the recipe because your using 5 times as much sugars. So for the flour 3*5=15

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What is three equivalent ratios for 10/12

goldfiish [28.3K]

Answer:

5:6

20:24

30:36

Step-by-step explanation:

In order to find an equivalent ratio, you have to multiply or divide your numerator and denominator by the same number.

For example:

10/12 x 3/3

30/36 = 30:36

10/12 is equivalent to 30:36

3 0

4 years ago

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What is the range of y = sin x?

Greeley [361]

Answer:

See below

Step-by-step explanation:

The function $f(x)=sin(x)$ oscillates between -1 and 1, so the range is $-1\leq x\leq 1$ .

7 0

3 years ago

F(x) = Vx - 14. Find the inverse of f(x).

olganol [36]

b

Step-by-step explanation:

<h3>correct me if im wrong </h3>

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2 years ago

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What is the slope of a line perpendicular to the line whose equation is y = 2x + 5?

anastassius [24]

B = -1/2
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8 0

3 years ago

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The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago