Which numbers are equivalent to 3/10

Mathematics

1 answer:

Sedbober [7]4 years ago

8 0

Answer:

Multiply numerator and denominator with same number to gwt the answers . There are infinitely many numbers

3/10 × 2/2 = 6/20

3/10 × 5/5 = 15/50

3/10 × 10/10 = 30/100

And so on

You might be interested in

Integral of 5xsqrt1-x^4

laila [671]

$\displaystyle\int5x\sqrt{1-x^4}\,\mathrm dx$

Take $x=\sqrt y$ , so that $y^2=x^4$ and $\dfrac{\mathrm dy}{2\sqrt y}=\mathrm dx$ . Note that this assumes $x\ge0$ and so requires $y\ge0$ .

$\displaystyle5\int\sqrt y\sqrt{1-y^2}\dfrac{\mathrm dy}{2\sqrt y}=\frac52\int\sqrt{1-y^2}\,\mathrm dy$

Now take $y=\sin z$ , so that $z=\arcsin y$ . Note that for this invertibility condition to hold, we require that $-\dfrac\pi2\le z\le\dfrac\pi2$ , which means $-1\le y\le1$ . But since we already fixed $y\ge0$ with the previous substitution, we thus have $0\le y\le1$ , which in turn restricts us to $0\le z\le\dfrac\pi2$ . So with this substitution, we have $\mathrm dy=\cos z\,\mathrm dz$ , which gives

$\displaystyle\frac52\int\sqrt{1-\sin^2z}\cos z\,\mathrm dz$
$=\displaystyle\frac52\int\sqrt{\cos^2z}\cos z\,\mathrm dz$
$=\displaystyle\frac52\int|\cos z|\cos z\,\mathrm dz$

Now over the interval $0$ , we have $\cos z>0$ , which means $|\cos z|=\cos z$ , and so the integral is equivalent to

$\displaystyle\frac52\int\cos^2z\,\mathrm dz=\frac54\int(1+\cos2z)\,\mathrm dz$
$=\dfrac54z+\dfrac58\sin2z+C$
$=\dfrac54z+\dfrac54\sin z\cos z+C$
$=\dfrac54\arcsin y+\dfrac54\sin(\arcsin y)\cos(\arcsin y)+C$
$=\dfrac54\arcsin y+\dfrac54y\sqrt{1-y^2}+C$
$=\dfrac54\arcsin(x^2)+\dfrac54x^2\sqrt{1-x^4}+C$

8 0

3 years ago

There are 480 jellybeans in an 8-ounce jar. How many jellybeans are there per ounce in the jar?

Alja [10]

The answer would be 60. This is because 480/8=60.

7 0

3 years ago

Read 2 more answers

Hey does anyone know if the answer is nonexistent?

Trava [24]

Answer:

Non-existent is the answer.