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ziro4ka [17]
3 years ago
9

Jamiya jogged 4.8 miles each day for 21 days last a month. how many miles did she jog last month

Mathematics
2 answers:
son4ous [18]3 years ago
8 0

she jogged 100.8 miles

algol [13]3 years ago
5 0

Hey!

Jamiya jogged 4.8 miles each day. She did this for 21 days. That means you have to multiply 4.8(each day) by 21(days) .

4.8 \times 21 = 100.8

<em>Jamiya jogged 100.8 miles last month</em>

Good luck and hope this helps! :)

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Given: Q = 7m + 3n, R = 11 - 2m, S = n + 5, and T = -m - 3n + 8.<br> Simplify R - [S + T].
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11-2m-(n+5+(-m)-3n+8)
11-2m-n-5-m+3n-8
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The total fare for two adults and three children on an excursion boat is $14. If each childs fare is one half of each adults far
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Make each adult x and each kid 5x
 and
set equal to 14.
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PLS HELP FAST. CORRECT ANSWER WILL BE MARKED BRAINLIEST
Marianna [84]

Answer:

it a or the first one or whatevr u wanna call it jsut #1

Step-by-step explanation:

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he yearbook club had a meeting. The meeting had 24 people, which is three-fourths of the club. How many people are in the club
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32 people

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Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity. In the given triangle ABC, angle A
lana66690 [7]

The relationship between the lengths of the sides of a right triangle are

given by Pythagoras theorem.

  • Part A: <u>ΔABC is similar to ΔADC</u>
  • Part B: ΔABC and ΔADC are similar according <u>AA similarity postulate</u>
  • Part C: <u>DA = 6</u>

Reasons:

Part A:

∠A = 90°

Segment AD ⊥ Segment BC

Location of point D = Side BC

Part A: In triangle ΔABC, we have;

∠A = 90°, ∠B = 90° - ∠C

In triangle ΔADC, we have;

∠ADC = 90°, ∠DAC = 90° - ∠C

∴ <u>ΔABC is similar to ΔADC</u> by Angle-Angle, AA, Similarity Postulate

Part B: The triangles are similar according to <u>AA similarity postulate</u>,

because two angles in one triangle are equal to two angles in the other

triangle and therefore, by subtraction property of equality, the third angle

in both triangles are also equal.

Part C: The length of DB = 9

The length of DC = 4

Required: Length of segment DA

In triangle ΔABD, we have;

∠BDA = 90°= ∠ADC

∠DAC ≅ ∠B by Congruent Parts of Congruent Triangles are Congruent

Therefore;

ΔABD ~ ΔADC by AA similarity, which gives;

\displaystyle \frac{\overline{DA}}{\overline{DC}}  = \frac{\overline{BD}}{\overline{DA}}

\overline{DA}^2 = \overline{DC} \times \overline{BD}

Which gives;

\overline{DA}^2 = 4 × 9 = 36

\overline{DA} = √(36) = 6

\overline{DA}<u> = 6</u>

Learn more here:

brainly.com/question/2269451

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