When the squared terms are of different signs, the equation generally describes a hyperbola. This one has its vertices at x=±30, so the parameters of interest are
domain: (-∞, -30] ∪ [30, ∞)
range: (-∞, ∞)
Answer:
2.5 dollars
Step-by-step explanation:
<em>f(-4) = 13</em>
- <em>Step-by-step explanation:</em>
<em>Hi there ! </em>
<em>f(x) = 0.5x + 15</em>
<em>replace x = - 4</em>
<em>f(-4) = 0.5×(-4) + 15</em>
<em>= - 2 + 15</em>
<em>= 15 - 2</em>
<em>= 13</em>
<em>Good luck !</em>
Answer:
9B^2-12B+4
Step-by-step explanation:
use (a-b)^2 = a^2-2ab+b^2
(3B)^2 - 2x3B x 2 +2^2
raise a product to a power
9B^2-12B+4
Answer:
Hello,
Answer :Rotation of 90° clockwise by the origin O, and translation 2 units to the left
Step-by-step explanation:
