The discounted amount of pair of pants is $37.4
<u>Solution:</u>
Given, A pair of pants regularly costs $68.
The pants are on sale for 45% of the original price.
We have to find that how much will the discount be?
Now, <em>discounted amount = original price – sold price
</em>
Discounted amount = original price – 45% of original price
Discounted amount = $68 – 45% of $68
Hence, the discounted amount is $37.4
The correct option is (B) show that Mrs. Deverell continues to be diminished in her new home.
<h3>
What does line 73 described?</h3>
In line 73, the author compares Mrs. Deverell to an "intimidated child" primarily in order to -
- Mrs. Deverell had no part to perform in her forever residence with Angel—all housekeeping work were to be left to a servants alone, and all other obligations were to be taken over from Angel.
- Mrs. Deverell would given situation wander all around house, bored, when she had nothing to do.
- The author utilizes the metaphor of a scared child in this situation.
- As a result, this analogy conveys to the reader Mrs. Deverell's limited status in her new home.
Therefore, according to the writer; in the line 73 the best description for the intimidated child is shown by option B.
To know more about the child, here
brainly.com/question/28154633
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Answer:
(- 4, 1 )
Step-by-step explanation:
A translation (x + 1), y - 3 ) means add 1 to the original x- coordinate and subtract 3 from the original y- coordinate.
B = (- 5, 4 ), thus
B' = (- 5 + 1, 4 - 3 ) = (- 4, 1 )
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Step-by-step explanation:
Answer:
The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 40.6 - 0.2 = 40.4 words per minute.
The upper end of the interval is the sample mean added to M. So it is 40.6 + 0.2 = 40.8 words per minute.
The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.
