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katrin [286]
4 years ago
9

Use the table to find the residual points. A 4-column table with 5 rows. The first column is labeled x with entries 1, 2, 3, 4,

5. The second column is labeled given with entries negative 0.7, 2.3, 4.1, 7.2, 8. The third column is labeled predicted value with entries negative 0.28, 1.95, 4.18, 6.41, 8.64. The fourth column is labeled residual value with all entries blank. Which residual plot is the correct one for the data?
Mathematics
1 answer:
Readme [11.4K]4 years ago
8 0

Answer:

What is the change for each consecutive input?

✔ 1

What is the change for each consecutive output?

✔ 0.35

What is the rate of change for the relationship?

✔ 0.35

Step-by-step explanation:

The change for each input is 1 beacause the inputs are 10,11,12,13

The change for each consecutive output is 0.35 beacuse we need to subtract 4.1 from 3.75

The rate of change for the relationship is also 0.35

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Answer:

6

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7 0
3 years ago
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4. Nine fruit juice bottles contain 4 1/2 litres of fruit juice between them.
brilliants [131]

Answer:

2\frac{1}{2} litres or 2.5 litres

Step-by-step explanation:

From the question, 9 fruit juice bottles contain 4\frac{1}{2} litres of fruit juice. Therefore, to find how many litres of fruit juice would be contained in 5 fruit juice bottles, you multiply 5 by 4\frac{1}{2} litres and you divide the product by 9.

i.e. Let the quantity of the fruit juice for 5 bottles be x.

9 juice bottles ===> 4\frac{1}{2} litres

5 juice bottles ===> x

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x = 2.5 litres or 2\frac{1}{2} litres

Hope this helps!!!

3 0
3 years ago
tickets to a play cost $11 each. There is also a service charge of $4 per order. Write ab equation for the relationship that giv
abruzzese [7]
Y=11x+4. formula: y=mx+b. insert the number of tickets where x is times 11 then add 4 to your total
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4 years ago
It took my question down twice here's a real math question I guess
aliina [53]

Answer:

n-3

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Step-by-step explanation:

<u>First inequality:</u>

<u />n+8

Therefore, this inequality restricts:

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<u>Second inequality:</u>

< 8+n-3

Therefore, this inequality restricts:

n \in \mathrm{R};\: n>-3

Therefore, with both of these restrictions together, we have:

\fbox{$n \in \mathrm{R}; n-3$}\\\mathrm{or\:}\fbox{$n-3$}\\\mathrm{or\:}\fbox{$(-\infty, -10)\cup(-3,\infty)$}.

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Answer:

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