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2 years ago

What is the least two common multiplication 2 and 5

1 answer:

7 0

LCM of 2 and 5 =10
The LCM of 2 and 5 is the smallest positive integer 10 that is divisible by both 2 and 5 without any remainder.

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Y is less than the product of 4 and x

sasho [114]

If you’re asking for the equation..

y < 4x

5 0

3 years ago

Read 2 more answers

Solve for x and graph the solution on the number line below

Ray Of Light [21]

Answer:

x=4

Step-by-step explanation:

x=4 because -4/2 is to -2

3 0

3 years ago

Factories A, B and C produce computers. Factory A produces 4 times as manycomputers as factory C, and factory B produces 7 times

Elina [12.6K]

Answer:

The probability is $P(A') = 0.485$

Step-by-step explanation:

Let assume that the number of computer produced by factory C is k = 1

So From the question we are told that

The number produced by factory A is 4k = 4

The number produced by factory B is 7k = 7

The probability of defective computers from A is $P(A) = 0.04$

The probability of defective computers from B is $P(B) = 0.02$

The probability of defective computers from C is $P(C) = 0.03$

Now the probability of factory A producing a defective computer out of the 4 computers produced is

$P(a) = 4 * P(A)$

substituting values

$P(a) = 4 * 0.04$

$P(a) = 0.16$

The probability of factory B producing a defective computer out of the 7 computers produced is

$P(b) = 7 * P(B)$

substituting values

$P(b) = 7 * 0.02$

$P(b) = 0.14$

The probability of factory C producing a defective computer out of the 1 computer produced is

$P(c) = 1 * P(C)$

substituting values

$P(c) = 1 * 0.03$

$P(b) = 0.03$

So the probability that the a computer produced from the three factory will be defective is

$P(t) = P(a) + P(b) + P(c)$

substituting values

$P(t) = 0.16 + 0.14 + 0.03$

$P(t) = 0.33$

Now the probability that the defective computer is produced from factory A is

$P(A') = \frac{P(a)}{P(t)}$

$P(A') = \frac{ 0.16}{0.33}$

$P(A') = 0.485$

3 0

4 years ago

Write the coordinates of the vertices after a translation 6 units left and 2 units down.

jenyasd209 [6]

Answer:

Answer below.

Step-by-step explanation:

K'(-7,0) L'(-5,3) M'(-7,4) N'(-9,3)

4 0

3 years ago

What is the number between 0.4 and 0.5?

Vlad1618 [11]

<span>There are infinite numbers between 0.4 and 0.5. The reason is that there are infinite rational as well as irrational numbers between 0.4 and 0.5, therefore, we cannot exactly give all the numbers between 0.4 and 0.5.
</span>
These are <span>the numbers</span>

0.41,0.42,0.43.0.44,0.45,0.46,0.47,0.48,0.49

6 0

4 years ago