Answer:
uh picture?
Step-by-step explanation:
Plug in the given numbers (x) to the equation.
For example, let's take the first value it gives us.
-10(-2) +y=4
20+y=4
y=-16
Then you would put that on the table, and plug in the next value(s).
Hope this helped!
The equation of the tangent line at x=1 can be written in point-slope form as
... L(x) = f'(1)(x -1) +f(1)
The derivative is ...
... f'(x) = 4x^3 +4x
so the slope of the tangent line is f'(1) = 4+4 = 8.
The value of the function at x=1 is
... f(1) = 1^4 +2·1^2 = 3
So, your linearization is ...
... L(x) = 8(x -1) +3
or
... L(x) = 8x -5
Guess ur not passing today