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3 years ago

Use the graphing calculator to graph the parent function.

Mathematics

2 answers:

san4es73 [151]3 years ago

6 0

Answer:

What happens when h is positive?

The asymptote of the graph shifts right by that amount.

What happens when h is negative?

The asymptote of the graph shifts left by that amount.

What happens when k is positive?

The entire graph shifts up by that amount.

What happens when k is negative?

The entire graph shifts down by that amount.

sammy [17]3 years ago

4 0

Answer: Right, Left, Up, Down

Step-by-step explanation:

just did it

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Use the linear approximation (1+x)^kapprox 1+kx to find an approximation for the function f(x) for values of x near zero.

padilas [110]

A) approx = 1-8x
b) f(x) -8(1-x)^-1 approx = -8(1+x) = -8 - 8x
because 1/x = x^-1...

c) f(x) = (1+x)^-1/2    approx = 1- 1/2x
d) f(x) = (4+x^2)^1/2   approx = 4 + 1/2x^2
e) f(x) = (6+3x)^1/3   approx = 6+x

8 0

3 years ago

JJ has two dogs. The combined weight of the two dogs is 60lbs. The larger

siniylev [52]

Answer:

The larger dog weighs 40 pounds and the smaller dog weighs 20 pounds

Step-by-step explanation:

7 0

3 years ago

PLEASE HELP! URGENT WILL GIVE BRAINLEST! PLEASE ANSWER ALL QUESTIONS!!! IF YOU DON'T I WILL REPORT.

Nesterboy [21]

Answer:

1. b) 135°, 225°

2. c) 0°, 180°

3. a) π/2

4. b) 30°, 150°, 210°, 330°

5. a) 1.25 radians and 4.39 radians

Step-by-step explanation:

Question 1

$\begin{aligned}\cos \theta & = -\dfrac{\sqrt{2}}{2}\\\implies \theta & = \cos^{-1}\left(-\dfrac{\sqrt{2}}{2}\right)\\\\& = 135^{\circ} \pm 360^{\circ}n, 225^{\circ} \pm 360^{\circ}\\\\& = 135^{\circ}, 225^{\circ}\quad \textsf{for}\:0^{\circ}\leq \theta < 360^{\circ}\end{aligned}$

Question 2

$\begin{aligned}\cos^2 \theta-1 & = 0\\\implies \cos^2 \theta & = 1\\\cos \theta & = \pm1\\\theta & = \cos^{-1}(\pm1)\\& = 0^{\circ} \pm 360^{\circ}n, 180^{\circ} \pm360^{\circ}n\\& = 0^{\circ}, 180^{\circ}\quad \textsf{for}\:0^{\circ}\leq \theta < 360^{\circ}\end{aligned}$

Question 3

$\begin{aligned}\sin \theta & = 1\\\implies \theta & = \sin^{-1}(1)\\\theta & = \dfrac{\pi}{2}\pm2\pi n\\\theta & = \dfrac{\pi}{2}\quad \textsf{for}\:0 \leq \theta < 2 \pi \end{aligned}$

Question 4

$\begin{aligned}3 \tan^2 \theta-1 & = 0\\\implies \tan^2 \theta & = \dfrac{1}{3}\\\tan \theta & = \pm\dfrac{1}{\sqrt{3}}\\\theta & = \tan^{-1}\left(\pm\dfrac{1}{\sqrt{3}}\right)\\& = 30^{\circ}\pm180^{\circ}n, 150^{\circ}\pm180^{\circ}n\\& = 30^{\circ}, 150^{\circ}, 210^{\circ}, 330^{\circ}\quad \textsf{for}\:0^{\circ}\leq \theta < 360^{\circ}\end{aligned}$

Question 5

$\begin{aligned}2 \tan \theta -6 & = 0\\\implies \tan \theta & = 3\\\theta & = \tan^{-1}(3)\\\theta & = 1.25\pm \pi n\\\theta & = 1.25, 4.39 \quad \textsf{for}\:0^{\circ}\leq \theta < 2 \pi \end{aligned}$

5 0

2 years ago

Read 2 more answers

The linear function is represented by the equation y = – 2. What can be determined of this equation written in slope-intercept f

Radda [10]

Answer:

The y-intercept is -2

Step-by-step explanation

y= -2 is a horizontal line, so it would not have a slope. Secondly, it can only intersect the y- axis at one place and that is at -2.

Hope this helps

6 0

3 years ago

Which equation results from taking the square root of both sides of (x – 9)2 = 81?

seropon [69]

In the question "Which equation results from taking the square root of both sides of (x – 9)2 = 81?" The correct answer is x - 9 = +/- 9. Taking the square root of both sides of the equation (x - 9)^2 = 81 will give: sqrt(x - 9)^2 = sqrt(81) x - 9 = +/- 9 Solving the equation results in two equation: x - 9 = 9 and x - 9 = -9 x = 9 + 9 and x = -9 + 9 x = 18 and x = 0

8 0

4 years ago

Read 3 more answers