If "C" is the number of carrots, then the phrase "Max has more than 5 carrots" can be written like this:
![c\ \textgreater \ 5](https://tex.z-dn.net/?f=c%5C%20%5Ctextgreater%20%5C%205)
: the number of carrots that Max has is bigger than 5.
However, we can't solve it without any additional information, all we know is that
Answer:
1138
Step-by-step explanation:
From the information given:
We can represent it perfectly in an exponential form:
![m = p(q)^x](https://tex.z-dn.net/?f=m%20%20%3D%20p%28q%29%5Ex)
where;
p = initial value = 120
q = base of the exponential form
q = 1 + r
here; r = rate in decimal = 10% = 0.1
Then q can now be = 1 + 0.1 = 1.1
Replacing it into the exponential form, we get:
![m = 120(1.1)^x](https://tex.z-dn.net/?f=m%20%3D%20120%281.1%29%5Ex)
where;
x = number of days and m = number of shoppers
Thus:
For the first day:
![m = 120(1.1)^x](https://tex.z-dn.net/?f=m%20%3D%20120%281.1%29%5Ex)
m = 120
For the second day:
![m = 120(1.1)^1](https://tex.z-dn.net/?f=m%20%3D%20120%281.1%29%5E1)
m = 132
For the third day:
![m = 120(1.1)^2](https://tex.z-dn.net/?f=m%20%3D%20120%281.1%29%5E2)
m = 145.2
For the fourth day
![m = 120(1.1)^3](https://tex.z-dn.net/?f=m%20%3D%20120%281.1%29%5E3)
m = 159.72
For the fifth-day
![m = 120(1.1)^4](https://tex.z-dn.net/?f=m%20%3D%20120%281.1%29%5E4)
m = 175.692
For the sixth-day
![m = 120(1.1)^5](https://tex.z-dn.net/?f=m%20%3D%20120%281.1%29%5E5)
m = 193.2612
For the seventh-day
![m = 120(1.1)^6](https://tex.z-dn.net/?f=m%20%3D%20120%281.1%29%5E6)
m = 212.58732
Thus; the total numbers of shoppers for the first 7 days is:
![= 120+ 132 + 145.2 + 159.72 + 175.692+193.2612+212.58732](https://tex.z-dn.net/?f=%3D%20120%2B%20132%20%2B%20145.2%20%2B%20159.72%20%2B%20175.692%2B193.2612%2B212.58732)
= 1138.46052
≅ 1138
Answer:
2
Step-by-step explanation:
The answer you want is going to be A
Hope it helps!!
<span>D: a line passing through the points (2, –6) and (4, –16)</span>