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Irina-Kira [14]
3 years ago
11

Solve this proportion x/14 6/21

Mathematics
1 answer:
Gemiola [76]3 years ago
5 0

Answer:

X=4

Step-by-step explanation:

Solution: x equals 4

x/14-(6/21)=0

1. Simplify 2/7

x/14- 2/7 is 0

It’s too much steps

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Answer:

3/4-7/9+2/3=0.63

Step-by-step explanation:

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Help with this question plzz
svlad2 [7]

Answer:

I think it is 4 white and 3 blue

Step-by-step explanation:

Because they have 3 cups of white then 6 cups of white so i think they multiplied it. Then they have 4 cups of blue then 8 cups of blue. So if you multiply it, it will give you the answer. I hope this is right and it helped and can you mark me brainliest!!!!!!!!

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2 years ago
X y
xenn [34]
B) y = 4x

X| * |Y|
2|2*4|8 |
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businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

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2 years ago
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Harlamova29_29 [7]
Solve the equation for x by finding a, b and c of the quadratic then applying the quadratic formula

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