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astraxan [27]
2 years ago
8

Put brackets in the calculation below to make it correct. 15 - 4 x 2 + 1 = 3

Mathematics
1 answer:
bagirrra123 [75]2 years ago
3 0
If you put brackets around (2+1), your method of working is: 
1) 15-4*(2+1)=3 
2) 15-4*3=3
3) 15-12=3
You don't need any more brackets, as the BIDMAS (brackets, Indices, division, multiplication, addition, subtraction) rule does the rest of the job for you. 
The answer is therefore: 15-4*(2+1)=3
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E, D, B, A, C, F

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A man runs the London marathon at an average speed of 8mph the route is 26 miles what was his time in hours and minutes
user100 [1]

Answer:

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4 0
2 years ago
Solve the system of equations by substitution <br> y= 3x - 10<br> 3x + 2y = 16
Natalija [7]
Y= 3x - 10
<span>3x + 2y = 16

3x+2(3x-10)=16
3x+6x-20=16
9x-20=16
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y=3x-10
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5 0
3 years ago
A student needs to select 3 books from 3 different mathematics, 3 different physics and 1 history books. What is the probability
Gnesinka [82]

Answer:

Probability that one of them is mathematics and other two are either physics or history books = 0.51

Step-by-step explanation:

Given - A student needs to select 3 books from 3 different mathematics, 3 different physics and 1 history books.

To find - What is the probability one of them is mathematics and other two are either physics or history books ?

Solution -

Given that,

A student needs to select 3 books from 3 different mathematics, 3 different physics and 1 history books.

So,

Total number of books = 3 + 3 + 1 = 7

The student has to select 3 books

So, Total number of ways = ^{7} C_{3} = 35

So,

Probability that one of them is mathematics and other two are either physics or history books is -

= \frac{^{3} C_{1}. ^{4} C_{2}  }{^{7} C_{3}}

= \frac{(3)(6)}{35}

= \frac{18}{35}

= 0.51

⇒Probability that one of them is mathematics and other two are either physics or history books = 0.51

8 0
2 years ago
F(x)= 1/25(∣6x∣+4x) f(-45)= what
svlad2 [7]

Answer:

f=-45

therefore

1/25(-270-180)

1/25(-450)

-18

4 0
3 years ago
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