One difference is the number of double bonds in the fatty acid chain
O+ 1 in 3 <span>37.4%
</span>O- 1 in 15 <span>6.6%
</span>
O- can receive O-
O+ can receive O+, O-
O can receive<span> O, A, B, AB</span>
Answer:
The correct answer is option D which is release of water from the vacuoles.
Explanation:
The difference in second plant from the first one is rigidity. Second one is wilted and not rigid. This is due to the release of water from the vacuoles in the cell of plants.
Vacuoles are present in the center of plant cell. They are usually filled with water and provide structural support to the cell.
In the absence of water filled vacuoles, plants shoots are wilted as in case of second plant.
Answer:
Even a slight reproductive advantage will eventually lead to the elimination of the less well adapted of two competing species
Explanation:
The competitive exclusion describes relationship between two species that compete for the limiting sources, and cannot coexist. It is enough for one species to have slightly advantage to be dominant over the other. As a consequence, other species (the weaker one) will be extincted (shift to a different ecological niche).
1) To calculate the population density you first need to know how many <span>squirrels form that population.
To calculate the number of</span><span> squirrels:
1500</span> squirrels is the capacity, so it's equivalent to 100%
So how much squirrels are present in 80% of the area:
1500----100 %
x----------80 %
x= 1200 <span>squirrels
</span>
2)Population Density equals the number of squirrels divided by the land area
In the first part was calculated the number of squirrels and the exercise gives us the area in hectares so the only thing left to do is divide them.
(since this exercise doesn't specify that the area needs to be in a certain measurement we can use hectares)
Population Density = 1200/ 150
<span>The population density of the squirrels is 8 per hectare</span>
