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Oksanka [162]
3 years ago
9

5) Telephone numbers in the

Mathematics
1 answer:
rodikova [14]3 years ago
3 0

Answer:

6,400,000,000 (6.4 billions)

Step-by-step explanation:

We have a total of 10 digits, and each digit was 10 possibilities of being filled, except the first digit of the area code and first digit of the telephone number, that have only 8 possibilities.

So if 8 digits have 10 possible values and 2 digit has 8 possible values, the number of possible telephone numbers is:

10^8 * 8^2 = 6,400,000,000 (6.4 billions)

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No problem ;)

Step-by-step explanation:

1/4: 0.25

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3/4: 0.75

4/4(1): 1

<em>Hope </em><em>this</em><em> </em><em>helps </em><em>you!</em>

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GREYUIT [131]

Answer:

99.7%

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3 years ago
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spin [16.1K]
The other endpoint is (1, -17).

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m=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Using our midpoint and endpoint, we have:
(6, -11) = (\frac{11+x_2}{2}, \frac{-5+y_2}{2})&#10;\\&#10;\\6=\frac{11+x_2}{2} \text{ and } -11=\frac{-5+y_2}{2}&#10;

For the first equation (to find the x-coordinate) we will multiply both sides by 2:
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For the second equation (the y-coordinate) we multiply both sides by 2:
-11\times2=\frac{-5+y_2}{2}\times 2&#10;\\&#10;\\-22=-5+y_2

Add 5 to both sides:
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4 0
3 years ago
If 3x - 6 = 21, what is the value of x - 2 ?
lora16 [44]
3x-6=21
Or,3x=27
Or,x=27/3
Or,x=9
So,Now,
X-2=9-2
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