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Lana71 [14]
4 years ago
5

What is the standard form for the quadratic function? g(x)=(x+1)2−2 g(x)=x2−1 g(x)=x2−2x−4 g(x)=x2+2x−1 g(x)=x2−3

Mathematics
1 answer:
serious [3.7K]4 years ago
6 0

Answer:

x^2 + 2x - 1

Step-by-step explanation:

g(x)=(x+1)2−2 would be a quadratic if you'd write it like this:  g(x)=(x+1)^2−2.

This expands to g(x) = x^2 + 2x + 1 - 2  =  x^2 + 2x - 1

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Answer:

12.34

Step-by-step explanation:

For divide by the number then you get the answer

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4 years ago
What is 3/4 / 1/6? (please help)
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It is 4 1/2. If you keep the first number switch the division symbol into a multiplication sign and find the reciprocal of the last number you would get this.

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3 years ago
Read 2 more answers
Factories fully. X to the power of three - x
spayn [35]

The expression x³ - x when factored out is x(x -1)(x + 1)

<h3>How to determine the factored expression?</h3>

From the question, we have the following expression that can be used in our computation:

X to the power of three - x

Express the expression properly

So, we have the following representation

x³ - x

The terms of the above expression are:

x³ and x

And the factor of x³ and x

Factor = x

So, we divide x³ and x by x

The results of these divisions are

x³/x = x²

x/x = 1

So, we have the following results

(x³ - x) = x(x² -1)

Express x² -1 as a difference of two squares

So, we have

(x³ - x) = x(x -1)(x + 1)

Hence, the factored expression is x(x -1)(x + 1)

Read more about expressions at

brainly.com/question/18631189

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7 0
1 year ago
Explanation of Baye's theorem.
ELEN [110]

I will be including both an basic explanation of what it is and its proof.

I'm guessing you are either learning about conditional probability at school or preparing for competitions.

Baye's theorem states:

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

That is the theorem itself and it means that the probability that event A happens given B is true equals the probability event B happens given A is true times the probability event A happens divided by the probability B happens.

That was the basic of the theorem and the proof of this is basically just testing how well you understand what conditional probability is.

P(A|B)=\frac{P(AintersectB)}{P(B)}

P(B|A)=\frac{P(BintersectA)}{P(A)}

Now we know that the probably that A and B both happens is the same as the probably that B and A both happens.

Therefore P(A|B) can be seen as P(B|A) multiplied by P(A) and then divided by P(B) which gives the right hand side of the first equation. And this is basically the theorem.

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

**Note P(B) have to be not equal to 0 because having a 0 in the denominator would make this equation undefined.

If you have any questions or need further explanations please ask me in the comments of the answer, I hope this helped!

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